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PolarNik [594]
3 years ago
10

A helicopter flies 168 miles against the wind in 2 hours; with the wind, it can fly 252 miles in the same amount of time. find t

he speed of the helicopter in still air.
Physics
2 answers:
Marysya12 [62]3 years ago
7 0

V = speed of helicopter

v = speed of wind

V - v = speed of helicopter against the wind

d = distance traveled against the wind = 168 mi

t = time of travel = 2 h

using the equation

speed = distance/time

V - v = d/t

V - v = 168/2

V - v = 84

v = V - 84 eq-1

V + v = speed of helicopter with the wind

D = distance traveled with the wind = 252 mi

t = time of travel = 2 h

using the equation

speed = distance/time

V + v = D/t

V + v = 252/2

V + v = 126

using eq-1

V + V - 84 = 126

V = 105 mph

posledela3 years ago
6 0

Let v_h be the speed of the helicopter in still air. Let v_w be the speed of the wind. Then, from the given information,

(v_h-v_w)2=168\\ (v_h+v_w)2=252\\

Adding the above 2 equations,

4v_h=168+252\\ 4v_h=420\\ v_h=105

The speed of the helicopter in still air 105 \;mi/hour

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Answer:

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g Two masses are involved in a collision on an axis (one dimensional). One mass is six times the mass of the second. Both masses
statuscvo [17]

Answer:

v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

It was a perfectly elastic collision.

Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

v₁f = ((m – 6m) / (m + 6m)) * (4) +  ((2*6m) / (m + 6m)) * (2)  

v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

e = - (v₁f - v₂f) / (v₁i - v₂i)   ⇒   e = - (0.5714 - 2.5714) / (4 - 2) = 1  

It was a perfectly elastic collision.

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