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4 years ago

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Which statements are true? Check all that apply. Based on both tables, there is no association between gender and enjoying danci

ng. Eve's table shows that those who enjoy dancing are likely girls. Bob's table shows that boys are likely to not enjoy dancing. The two tables will be identical since boys and girls have the same total number. The percentage of someone being a girl, given that the person enjoys dancing is lower than the percentage that someone enjoys dancing, given that the person is a girl.

1 answer:

Maru [420]4 years ago

6 0

Answer:

b c e

Step-by-step explanation:

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a population has a mean of 25 median of 24 and mode of 26 the standard deviation is 5 the value for the

Arada [10]

Complete Question

A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.

Answer:

The value of the 16th percentile is $x = 20$

The range for the middle 3 standard deviation is $10 \to 40$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 25$

The median is $m = 24$

The mode is $n = 26$

The standard deviation is $\sigma = 5$

Generally the 16th percentile is mathematically represented as

$P(x)= P(\frac{X - \mu }{ \sigma } \le \frac{x- 25 }{5} ) = 0.16[/teGenerally [tex]\frac{X - \mu}{\sigma } = Z(The \ standardized \ value \ of \ X )$

So

$P(x) = P(Z \le \frac{ x - 25}{5} ) = 0.16$

Now from the normal distribution table the z-score of 0.16 is

z = -1

$P(x) = P(Z \le \frac{ x - 25}{5} ) = P(Z \le -1 )$

=> $\frac{x- 25}{5} = -1$

=> $x- 25 = -5$

=> $x = 25-5$

=> $x = 20$

The range for the middle 3 standard deviation is mathematically represented

$\mu - 3\sigma \to \mu + 3\sigma$

$25 - 3(5 ) \to 25 + 3(5 )$

$10 \to 40$

3 0

3 years ago

the graph of a line in the xy-plane has slope of 7 and contains the point(6,28). A second line passes through the points (3,7) a

Maslowich

Answer:

x = 3

Step-by-step explanation:

We require the equations of the 2 lines.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

The line has slope = 7, hence

y = 7x + c ← is the partial equation

To find c substitute (6, 28) into the partial equation

28 = 42 + c ⇒ c = 28 - 42 = - 14

y = 7x - 14 → (1)

Calculate the slope of the second line using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (3, 7) and (x₂, y₂ ) = (- 1, - 13)

m = $\frac{-13-7}{- 1-3}$ = $\frac{-20}{-4}$ = 5, thus

y = 5x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (3, 7), then

7 = 15 + c ⇒ c = 7 - 15 = - 8

y = 5x - 8 → (2)

Solving (1) and (2) by equating the right sides

7x - 14 = 5x - 8 ( subtract 5x from both sides )

2x - 14 = - 8 ( add 14 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

The x- coordinate of the point of intersection is x = 3

6 0

3 years ago

Miranda needs 3.5 yards of fabric to make a curtain for her dining room window and 2.25 yards of the same fabric to make a match

schepotkina [342]

Answer:

Well, 3.5 yards + 2.25 = 5.75

Now, just subtract 6.5 - 5.75 = .75

So there will be .75 yards left over . Hope this helps!

PLEASE MARK BRAINLIEST!!!!

7 0

3 years ago

Read 2 more answers

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

At a carnival booth, customers had to guess how many jelly beans were in a jar. Samantha guessed there were 295 jelly beans. The

Julli [10]

Answer:

Samantha percent error was 18%.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers