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4 years ago

PLEASE HELP!!!!!!

Physics

2 answers:

kkurt [141]4 years ago

8 0

You have to do D=m/v which is Density equals mass over volume so you divide 3.1g and 0.35 that is 8.85

Helga [31]4 years ago

3 0

Hey there,

Density = Mass/Valume

D= 3.1/0.35

D= 8.86 g/cm3

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Which type of carbohydrate is the body unable to digest, but is still important for lowering cholesterol, balances glucose level

AysviL [449]

Answer:

Cellulose

Explanation:

Cellulose is the carbohydrate which is unable to be digested by body. Adding fiber's (cellulose) to one's diet reduces blood cholesterol level because soluble fiber dissolves in water to form a gel, which moves slowly through the intestines binding up fat, dietary cholesterol, bile salts, and sugar to be excreted. Once excreted, these are no longer available to build more cholesterol. Also cellulose remains undigested but is effectively making one gain more calories, so it helps prevents over eating.

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3 years ago

Astronomers determine that a certain square region in interstellar space has an area of approximately 2.4 \times 10^72.4×10 7

mafiozo [28]

Answer:

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Explanation:

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A = l²

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A is the area of the square

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3 years ago

An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and

Kobotan [32]

Answer:

Explanation:

Given that

The electric fields of strengths E = 187,500 V/m and

and The magnetic fields of strengths B = 0.1250 T

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The radius is (d/2)

= 0.2505m / 2 = 0.12525m

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The given formula to find the electric force is $F_{el}=qE---(ii)$

The velocity of electric field and magnetic field is said to be perpendicular

Electric field is equal to magnectic field

Equate equation (i) and equation (ii)

$Bqv=qE\\\\v=\frac{E}{B}$

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It is said that the particles moves in semi circle, so we are going to consider using centripetal force

$F_{ce}=\frac{mv^2}{r}---(iii)$

magnectic field is equal to centripetal force

Lets equate equation (i) and (iii)

$Bqr=\frac{mv^2}{r} \\\\\frac{q}{m}=\frac{v}{Br} \\\\\frac{q}{m} =\frac{15\times 10^5}{0.125\times0.12525} \\\\=\frac{15\times10^5}{0.015656} \\\\=95808383.23\\\\=958.1\times10^5C/kg$

Therefore, the particle's charge-to-mass ratio is $958.1\times10^5C/kg$

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Then 1/ 958.1 × 10⁵ C/kg

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8 0

4 years ago

An unknown material, m1 = 0.45 kg, at a temperature of T1 = 91 degrees C is added to a Dewer (an insulated container) which cont

goldenfox [79]

Answer:

Explanation:

Let the specific heat of material be s

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4 years ago

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trapecia [35]

Answer:

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Explanation:

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3 years ago