1. 40-0=40
3. 40/5=8
8 ml/s
you find the range of acceleration(step one)
divide by the time(step two)
Answer:
Explanation:
El impulso aplicado a la pelota produce una variación en su momento lineal.
J = m (V -Vo)
Conviene elegir positivo el sentido de la velocidad final.
J = 0,100 kg [40 - (- 20)] m/s = 6 kg m/s
Saludos Herminio
Answer:
juz taking points nvm no sry for u cos u too wasted point
Answer:
[1, 6, -2]
Explanation:
Given the following :
Initial Position of spaceship : [3 2 4] km
Velocity of spaceship : [-1 2 - 3] km/hr
Location of ship after two hours have passed :
Distance moved by spaceship :
Velocity × time
[-1 2 -3] × 2 = [-2 4 -6]
Location of ship after two hours :
Initial position + distance moved
[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]
= [3-2, 2+4, 4-6] = [1, 6, -2]
The first factor is wind speed, the second factor is wind duration, and the last factor is the fetch, the distance over which the wind blows without a change in direction.
all these factors determines the strength of a wave.
hope this helps :)
