Can someone please help me out with this ?

Physics

1 answer:

storchak [24]3 years ago

7 0

Answer:

The atomic number is the number over the symbol of the element in the periodic table and the atomic mass the number under it. An isotope is an atom with more or less neutrons than its regular form. a neon atom with mass number of 22 will have 12 neutrons in the nucleus and 10 protons, draw it with its 10 electrons. Two electrons go in the first level of energy and eight in the second. Draw a nucleus with 10 protons and 12 neutrons and an arc with 2 electrons around it and another arc with 8 electrons over the first arc.

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The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota

german

Answer:

Transverse wave and Longitudinal wave and Electromagnetic wave

Explanation:

An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc.
Most electromagnetic waves are transverse in nature.

4 0

3 years ago

PLEASE HELP

Sergeu [11.5K]

The vertical component of the initial velocity is $v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is $v_0_x = \frac{x}{t}$

The horizontal displacement when the object reaches maximum height is $X = \frac{xy}{gt^2} + \frac{x}{2}$

The given parameters;

the horizontal displacement of the object, = x

the vertical displacement of the object, = y

acceleration due to gravity, = g

time of motion, = t

The vertical component of the initial velocity is given as;

$y = v_0_yt - \frac{1}{2} gt^2\\\\v_0_yt = y + \frac{1}{2} gt^2\\\\v_0_y = \frac{y}{t} + \frac{1}{2} gt$

The horizontal component of the initial velocity is calculated as;

$x = v_0_xt\\\\v_0_x = \frac{x}{t}$

The time to reach to the maximum height is calculated as;

$T = \frac{v_f_y -v_0_y}{-g} \\\\T = \frac{-v_0_y}{-g} \\\\T = \frac{v_0_y}{g} \\\\T = \frac{1}{g} (v_0_y)\\\\T = \frac{1}{g} (\frac{y}{t} + \frac{1}{2} gt)\\\\T = \frac{y}{gt} + \frac{1}{2} t$