Answer:
1.275 m
Explanation:
Let the maximum height reached be h.
Here initial velocity, u = 5 m/s
Final velocity, V = 0
Use third equation of motion
V^2 = u^2 + 2 g h
0 = 25 - 2 × 9.8 × h
h = 25/19.6 = 1.275 m
Mu = 8.66 × 10^25 kg
Explanation:
centripetal force = gravitational force
where
m = mass of moon Ariel
mu = mass of Uranus
r = radius of Ariel's orbit
v = Ariel's velocity around Uranus
To find the velocity, we need to find the circumference of the no orbit and then divide it by the period (2.52 days):
circumference = 2πr = 2π×(1.91 × 10^8 m)
= 1.2 × 10^9 m
period = 2.52 days × (24 h/1 day)×(3600 s/1 hr)
= 2.18 × 10^5 s
v = (1.2 × 10^9 m)/(2.18 × 10^5 s)
= 5.5 × 10^3 m/s
(5.5 × 10^3 m/s)^2/(1.91 × 10^8 m) = (6.67 × 10^-11 m^3/kg-s^2)Mu/(1.91 × 10^8 m)^2
Solving Mu,
Mu = 8.66 × 10^25 kg
Answer:
The time taken by the airplane to take off, t = 11.46 s
Explanation:
Given data,
The initial velocity of the airplane, u = 24 m/s
The acceleration of the plane, a = 8 m/s
The distance covered until take off, d = 800 m
Using the III equation of motion,
v² = u² +2as
= 24² + 2 x 8 x 800
= 13376
v = 115.65 m/s
Using the first equation of motion,
v = u + at
t = (v-u) / a
= (115.65 - 24) / 8
= 11.46 s
Hence, the time taken by the airplane to take off, t = 11.46 s
Answer:
is B because 35 times 2.9 equals 101.5 and if you round it is 102
Answer:
1 N
Explanation:
First the equation is momentum = Force / distance
20 cm = 0.2 m
5 N/m = F / 0.2 m
F = 1 N
