Answer:
Option C
Crimp terminals
Explanation:
It's possible to crimp terminals using a multipurpose wiring tool. Since the tool  selected for use during crimping also depends on the volume of work, the multipurpose wiring tool is recommended for use when the volume is small to medium. Basically, crimping tools are sized according to the wire gauge that they can fit. Since multipurpose has different sizes, that's why it's used for crimping tools.
 
        
             
        
        
        
Answer:
It travels 1414 feets.
Explanation:
Let's take the length the bullet travels <em>l </em>as the hypotenuse of a right triangle and the height it reaches one of its sides. Since we got the angle α at which it was fired and the height <em>h</em> it reached, we can calculate <em>l</em> using the <em>sin(α)</em> function:

Replacing:

Solving and roundin to the nearest foot:

 
        
             
        
        
        
Answer:
Acceleration = 4 m/s²
Explanation:
Given the following data;
Force = 8 N
Mass = 2 kg
To find the acceleration of the block;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass. 
Mathematically, it is given by the formula;
 
 
Substituting into the formula, we have;
 
 
Acceleration = 4 m/s²
 
        
             
        
        
        
Answer:
good because piggy loves peppa pig :3
Explanation:
 
        
             
        
        
        
Answer:
2.083 V.
Explanation:
 Stopping potential is the potential that is required to stop the current to zero . This potential is applied externally to oppose the potential created by the photoelectric effect . It gives the measure the photoelectric potential being generated . 
 Here current drops to 25 μA to 19 μA by a potential of 500mV
Change in current 
= 25 - 19 = 6 μA 
Voltage requirement for unit reduction in current 
= 500 / 6 μA
To reduce current 0f 25 μA 
requirement of V = (500 / 6 )  x 25 =   2083.33 mV = 2.083 V.