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laiz [17]
3 years ago
10

If the input work on a machine is equal to it's output work. the machine has _____ efficiency.

Physics
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

100% efficiency

Explanation:

the machine has _100%_ efficiency.

(fill in the blank)

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A ski tow operates on a slope of angle 15.6 ∘ of length 340 m . The rope moves at a speed of 12.7 km/h and provides power for 53
GREYUIT [131]

Answer:

P = 34034.2 Watt

Explanation:

As we know that the slope angle is given as

\theta = 15.6^0

now the weight of the rider along the slope is given as

W = mgsin\theta

W = 69(9.81)sin15.6

W = 182 N

now total weight of all 53 riders along the slope is given as

F = 53 W

F = 9647.5 N

now the speed of the rope is given as

v = 12.7 km/h = 3.53 m/s

now the power required is given as

P = F.v

P = 9647.5(3.53)

P = 34034.2 Watt

3 0
3 years ago
The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm
Mama L [17]

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential  is given by;

\rm V=Ed

\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V=  10 \frac{Nm}{C} = 10 \frac{J}{C}  = 10 V.

The work is defined as the product of the potential difference and charge of an electron.

\rm W= 10 \times  1.602 x 10^{-19} \\\\\ \rm W=  1.6 x 10^{-18 }J

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

To learn more about the electric field refer to the link;

brainly.com/question/15071884

8 0
2 years ago
Choose the more reactive nonmetal. P or O
makkiz [27]
P always P because P is an awkward Dorian letter that can always be trusted
6 0
3 years ago
Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT include
Kaylis [27]

The electric filed in V/m is 1.58 * 10^6 V/m

<h3>What is the electric field?</h3>

We know that the electric field is obtained as the ratio of the voltage to the distance that separates the plates.

Thus;

E = V/d

E = electric field

V = voltage

d = distance of separation

E = 24 * 10^3 V/1.52 * 10^-2 m

E = 1.58 * 10^6 V/m

Learn more about electric field :brainly.com/question/8971780

#SPJ1

7 0
2 years ago
A running mountain lion can make a leap 10.0 mlong, reaching a maximum height of 3.0 m. What is the speed of the mountain lion j
nika2105 [10]

To solve this problem we will use the kinematic equations of descriptive motion of a projectile for which both the height reached and the distance traveled are defined. From this type of movement the lion reaches a height (H) of 3m and travels a horizontal distance (R) of 10 m. Mathematically the equations that describe this movement are given as,

H = \frac{v_0^2sin^2\theta}{2g}

R = \frac{v_0^2 sin 2\theta}{g}

Dividing the two equation we have that

\frac{H}{R}=\frac{\frac{v_0^2sin^2\theta}{2g}}{\frac{v_0^2 sin 2\theta}{g}}

\frac{H}{R}= \frac{sin^2\theta}{2}*\frac{1}{sin2\theta}

\frac{H}{R}= \frac{sin^2\theta}{2}*\frac{1}{2sin\theta cos\theta}

\frac{H}{R}= \frac{1}{4} \frac{sin\theta}{cos\theta}

\frac{H}{R}= \frac{1}{4} tan\theta

Substituting values of H and R, we get

\frac{3}{10} = \frac{1}{4} tan\theta

\theta = tan^{-1} \frac{12}{10}

\theta = 50.2\°

Substituting the value of \theta in equation we get,

H = \frac{v_0^2sin^2\theta}{2g}

v_0^2 = \frac{H 2g}{sin^2\theta}

v_0^2 = \frac{3*2*9.8}{sin^2(50.2)}

v_0^2 = 99.62

v_0 = \sqrt{99.62}

v_0 = 9.98m/s

Therefore the speed of the mountain lion just as it leaves the ground is 9.98m/s at an angle of 50.2°

5 0
3 years ago
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