Answer:
We cannot tell from the information given
Explanation:
Given;
mass of the box, m = 5 kg
first force, F₁ = 10 N
second force, F₂ = 5 N
(I) Assuming the two forces are acting horizontally in opposite direction, the resultant force on the box is calculated as;
∑Fx = 10 N - 5 N
= 5 N
Apply Newton's second law of motion;
∑Fx = ma
a = ∑Fx/m
a = 5 / 5
a = 1 m/s² in the direction of the 10 N force.
(II) Also, if the two forces are acting in the same direction, the resultant force is calculated as;
∑Fx = 10 N + 5 N
∑Fx = 15 N
a = 15 / 5
a = 3 m/s²
Therefore, the information given is not enough to determine the acceleration of the box.
To act as the Sun' was accepted but if you put 'sunlight' alone it was not accepted. The examiner wanted you to state that the infra red radiation was needed to warm up the water.
The mass of the first block will be three times the mass of the second block.
According to Newton's second law of motion, the force acting on a body is directly proportional to the acceleration as shown;


F is the acting force
m is the mass
a is the acceleration of the body
Given the following parameters
Constant force F = 1N
For the first block with the acceleration of "a"
1 = m₁a
a = m₁/1
m₁ = a .................1
For the second block, acceleration is thrice that of the first. This means;
F = m(3a)
1 = 3ma
..........................2
Divide both equations

From the calculation, we can conclude that the mass of the first block will be three times the mass of the second block.
Learn more here: brainly.com/question/19030143
By Newton's second law, the net force on the object is
∑ <em>F</em> = <em>T</em> - <em>mg</em> = - <em>ma</em>
where
• <em>T</em> = 25 N, the tension in the string
• <em>m</em> is the mass of the object
• <em>g</em> = 9.8 m/s², the acceleration due to gravity
• <em>a</em> = 2.0 m/s², the acceleration of the elevator-object system
Solve for <em>m</em> :
25 N - <em>m</em> (9.8 m/s²) = - <em>m</em> (2.0 m/s²)
==> <em>m</em> = (25 N) / (9.8 m/s² - 2.0 m/s²) ≈ 3.2 kg
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N