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8_murik_8 [283]
2 years ago
11

Why gravitational force at the center og earth is zero

Physics
2 answers:
KengaRu [80]2 years ago
8 0
F = G Mm/r²
mg = G Mm/r²
g = GM/r²
At centre of earth, r=0
g = GM/0
g =0
Anon25 [30]2 years ago
4 0

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

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\huge{\blue{\mathbb{HELLO\:BUDDY}}}

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❣️ ❣️ Follow me ❣️ Follow me

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\huge{\green{\tt{\underline{\underline{QUESTION:-}}}}}

Why value of 'g' is zero at center of Earth?

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\huge{\red{\tt{\underline{\underline{EXPLANATION:-}}}}}

When we move towards centre of earth, the mass is equally distributed in all directions.

The mass beneath you = Mass in front of you = Mass behind you

Thus, all the gravitational forces applied cancel each other and acceleration due to gravity (g) at centre of earth on centre of earth becomes zero (0).

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

\huge{\green{\tt{\underline{\underline{PROOF:-}}}}}

The general equation of acceleration due to gravity is;-

g = \frac{GM}{r^2}

Assuming earth to be a perfect sphere and considering its uniform density.

We make the following adjustments in the following equation.

g = \frac{GM}{r^2}

Multiplying and dividing RHS by volume 'V'.

g = \frac{GM}{V} × V × \frac{1}{r^2}

We know that;-

\frac{M}{V} = Density, ρ

Therefore,

g = \frac{ρGV}{r^2}

For sphere;-

V = \frac{4}{3}πr^{3}

This makes

g = \frac{4}{3}πr^{3} × \frac{ρG}{r^2}

g = \frac{4πρG}{3}

So, at center of Earth

since, r = 0

so, g = 0.

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\boxed{\underline{\green{\star{HOPE \: YOU\:GOT \:THE \:ANSWER.}}}}

\boxed{\underline{\pink{\star{MARK \: ME  \: BRAINLIEST.}}}}

\Large{\mathcal{\green{FOLLOW \: ME}}}

Thankyou

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A spring is 6.0cm long when it is not stretched, and 10cm long when a 7.0N force is applied. What force is needed to make it 20c
Artist 52 [7]

Answer:

Approximately 25\; {\rm N} (assuming that this spring is ideal.)

Explanation:

The displacement of a spring is the new length of the spring relative to the original length.

For example:

  • When the 6.0\; {\rm cm}-spring in this question is stretched to 10\; {\rm cm}, the displacement is x = (10\; {\rm cm} - 6.0\; {\rm cm}).
  • Likewise, if this spring is stretched to 20\; {\rm cm}, the displacement would be (20\; {\rm cm} - 6\; {\rm cm}).

If this spring is ideal, the force on the spring would be proportional to the displacement of the spring. In other words, if a force of F_{\text{a}} displaces this spring by x_{\text{a}}, while a force of F_{\text{b}} displaces this spring by x_{\text{b}}, then:

\displaystyle \frac{F_{\text{a}}}{x_{\text{a}}} = \frac{F_{\text{b}}}{x_{\text{b}}}.

In this question, it is given that a force of F_{\text{a}} = 7.0 \; {\rm N} would stretch this spring by x_{\text{a}} = (10\; {\rm cm} - 6.0\; {\rm cm}). Thus, the force F_{\text{b}} required to stretch this spring by x_{\text{a}} = (20\; {\rm cm} - 6.0\; {\rm cm}) would satisfy:

\displaystyle \frac{7.0\; {\rm N}}{10\; {\rm cm} - 6.0\; {\rm cm}}= \frac{F_{\text{b}}}{20\; {\rm cm} - 6.0\; {\rm cm}}.

Rearrange and solve for F_{\text{b}}:

\begin{aligned} F_{\text{b}} &= \frac{7.0\; {\rm N}}{10\; {\rm cm} - 6.0\; {\rm cm}} \, (20\; {\rm cm} - 6.0\; {\rm cm}) \\ &\approx 25\; {\rm N}\end{aligned}.

7 0
1 year ago
8. An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object? _______________
Sholpan [36]

Answer:

Mass of object is 0.5kg

Explanation:

Given the following data;

Force = 6N

Acceleration = 12m/s²

Mass =?

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

F = ma

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making mass (m) the subject, we have;

Mass (m) = \frac{F}{a}

Substituting into the equation;

Mass (m) = \frac{6}{12}

Mass, m = 0.5kg.

Therefore, the mass of the object is 0.5kg

5 0
2 years ago
Provide two ways that objects can become charged
kap26 [50]

Answer:

friction, conduction and induction

Explanation:

Had it in class I had it correct hope this helps.

8 0
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The law of conservation of momentum states that the total momentum of interacting objects does not change . This means the total
pickupchik [31]

Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass m travelling at a velocity \vec{v}. The momentum \vec{p} of this object would be:

\vec{p} = m \cdot \vec{v}.

For the law of conservation of momentum, consider two objects: object \rm a and object \rm b. Assume that these two objects collided with each other.

  • Let m_{\rm a} and m_{\rm b} denote the mass of the two objects.
  • Let \vec{v}_{\rm a}(\text{initial}) and \vec{v}_{\rm b}(\text{initial}) denote the velocity of the two object right before the interaction.
  • Let \vec{v}_{\rm a}(\text{final}) and \vec{v}_{\rm b}(\text{final}) denote the velocity of the two objects right after the interaction.
  • The momentum of the two objects right before the collision would be m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) and m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}), respectively.
  • The momentum of the two objects right after the collision would be m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) and m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final}), respectively.

The sum of the momentum of the two objects would be:

  • m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) right before the collision, and
  • m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final}) right after the collision.

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final}).

4 0
3 years ago
A 87 kg man has a total mechanical energy of 1780 J .If he is swinging downward and is currently 1.4 m above the ground, what is
borishaifa [10]

Answer:

6.4m/s

Explanation:

The total mechanical energy of the man is 1780J.

This mechanical energy is the energy due to the motion of the body and it is a form of kinetic energy.

 Also, mass  = 87kg

   Kinetic energy  = \frac{1}{2}   m v²

m is the mass

v is the velocity

           1780  =  \frac{1}{2} x 87 x v²

                v²  = 40.9

                v  = 6.4m/s

4 0
3 years ago
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