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DerKrebs [107]
4 years ago
5

Consider the roller coaster on the track. If you want to increase the kinetic energy of the roller coaster as it proceeds throug

h the course, what is the FIRST thing you should do?
A) Increase the height at point A.
B) Decrease the height at point A.
C) Increase the height at point B.
D) Decrease the height at point B.

Physics
1 answer:
a_sh-v [17]4 years ago
5 0

Answer:

The answer is A and D but if you want one anwer i think the anwer is A

Explanation:

You might be interested in
Una pelota se desliza hacia arriba por una pendiente se halla inicialmente a 6m de la parte más baja de dicha pendiente y tiene
jolli1 [7]

Answer:

a) vprom = - 0.6 [m/s] b) ver explicacion c) vf = 10.8 [m/s]

Explanation:

Para poder solucionar este problema debemos completar el enunciado del problema así como la pregunta, realizando una búsqueda en Internet encontramos el enunciado completo, así como la pregunta.

"Una pelota que se desliza hacia arriba por una pendiente se halla inicialmente a 6 m de la parte más baja de dicha pendiente y tiene una velocidad de 4 m/s. Cinco segundos después se encuentra a 3 m de la parte más baja. Si suponemos una aceleración constante, "

¿cual fue la velocidad media?

¿Cuál es el significado de una velocidad media negativa?

¿Cuáles son la aceleración media y la velocidad final?

Para facilitar esta solución debemos realizar un esquema del movimiento de la pelota en el plano inclinado. En la imagen adjunta se puede ver un esquema del movimiento de la pelota sobre el plano inclinado en los diferentes tiempos mencionados.

<u>¿cual fue la velocidad media?</u>

<u />

La velocidad media se debe calcular utilizando la expresión de velocidad = espacio / tiempo.

v_{prom}=x/t\\v_{prom}=(3-6)/5\\v_{prom}=-0.6 [m/s]

<u>¿Cuál es el significado de una velocidad media negativa? </u>

La velocidad media negativa significa que se dirige hacia abajo en sentido contrario

<u>¿Cuáles son la aceleración media y la velocidad final?</u>

<u />

x=v_{o}*t+0.5*a*t^{2} \\-3=(4)*(5)+0.5*a*(5)^2\\a=1.36[m/s^2]\\\\Velocity\\v_{f}=v_{o}+a*t = 4+(1.36*5)\\v_{f}=10.8[m/s]

6 0
3 years ago
A bicycle tire is spinning counterclockwise at 3.00 rad/s. During a time period Δt = 2.30 s, the tire is stopped and spun in the
emmasim [6.3K]

Answer:

Δω =  -6.00 rad/s

α = -2.61 m/s²

Explanation:

Step 1: Data given

A bicycle tire is spinning counterclockwise at 3.00 rad/s

Δt = 2.30 s

In theopposite (clockwise) direction, also at 3.00 rad/s

Step 2: Calculate the change in the tire's angular velocity Δω

Δω =  ωf -  ωi

ωf = - 3.00 rad/s

 ωi  = 3.00 rad/s

Δω =  ωf -  ωi  = -3.00 - 3.00 = -6.00 rad/s

Step 3: Calculate the tire's average angular acceleration α

α =  Δω /  ΔT

α = -6.00 rad/s /2.30s  

α = -2.61 m/s²

A negative angular acceleration means a decreasing angular velocity

6 0
4 years ago
Which numbers on the ph scale indicate an acid
KiRa [710]

Answer:

0 - 6.9 --> Acidic

Explanation:

4 0
3 years ago
a magnet has a 20 cm magnetic field if a piece of metal is 18 cm from the magnet will it be attracted or not
mina [271]

Answer:

yes

Explanation:

The metal is closer than 20 cm to the magnet which is in the magnetic field.

4 0
3 years ago
What is the % error in using g = 10.0 m/s^2? (Take the value ofg as 9.8 m/s^2)
Alenkasestr [34]

Answer:

So percentage error will be 2 %

Explanation:

We have given initial value of acceleration due to gravity g=10m/sec^2

And final value of acceleration due to gravity g=9.8m/sec^2

We have to find the percentage error

We know that percentage error is given by percentage\ error=\frac{initial\ value-final\ value}{initial\ value}\times 100

So percentage\ error=\frac{10-9.8}{10}\times 100=2 %

4 0
3 years ago
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