The purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
<h3>What is the importance of movement of the scapula during arm elevation?</h3>
The scapula is an important bone which is found in the shoulder and back region of the body.
The scapula enables and increases the range of motion of the arm with its motions.
During arm elevation, the scapula undergoes an upward rotational motion.
Therefore, the purpose of the scapula to move during arm elevation is increase the range of elevation of the arm.
Learn more about scapula motion at: brainly.com/question/5133017
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They use Newton to measure force
Answer:
U = 1 / r²
Explanation:
In this exercise they do not ask for potential energy giving the expression of force, since these two quantities are related
F = - dU / dr
this derivative is a gradient, that is, a directional derivative, so we must have
dU = - F. dr
the esxresion for strength is
F = B / r³
let's replace
∫ dU = - ∫ B / r³ dr
in this case the force and the displacement are parallel, therefore the scalar product is reduced to the algebraic product
let's evaluate the integrals
U - Uo = -B (- / 2r² + 1 / 2r₀²)
To complete the calculation we must fix the energy at a point, in general the most common choice is to make the potential energy zero (Uo = 0) for when the distance is infinite (r = ∞)
U = B / 2r²
we substitute the value of B = 2
U = 1 / r²
Explanation:
Gravitational potential energy
= mgh
= (2kg)(10N/kg)(5m)
= 100J.