initial speed of the ball by which it is kicked is 8 m/s
now the angle at which it is kicked is 20 degree
here we will have
now we will have
so if the ball again land on the ground at same level then we have
so total time will be 0.56 s
Jim is driving a 2268-kg pickup truck at 22 m/s and releases his foot from the accelerator pedal. The car eventually stops due t
1 answer:
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Explanation:
Given that,
Initial speed of the rock, u = 30 m/s
The acceleration due to gravity at the surface of the moon is 1.62 m/s².
We need to find the time when the rock is ascending at a height of 180 m.
The rock is projected from the surface of the moon. The equation of motion in this case is given by :
It is a quadratic equation, after solving whose solution is given by:
t = 7.53 s
or
t = 8 seconds
(e)If it is decending, v = -20 m/s
Now t' is the time of descending. So,
Let h' is the height of the rock at this time. So,
or
h' = 155 m
Answer:
The ratio of the orbital time periods of A and B is
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:
where
R = Radius of the orbit
Now,
For satellite A:
Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):