The Hydrogen bomb is a thermonuclear bomb where a fission reaction is used to trigger a fusion reaction.
Answer: Option A
<u>Explanation:
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The Concept of Hydrogen Bomb or H-Bomb is primarily based on nuclear fusion where different isotopes of hydrogen diffuse to fuse their atomic nuclei into a bigger atom, releasing a significant and enormous amount of energy that can ruin a half of the world.
A hydrogen or thermonuclear bomb contains a firearm, but the reaction process has two stages. Uses primary fission energy to activate the next fusion reaction. The energy out by the fusion is nearly four times more than the energy out during fission, which gives more power to a hydrogen bomb.
Answer: 0.56 m/s
Explanation:
Hi, to answer this question we have to apply the formula of the conservation of momentum.
m1 v1 = m2 v2 (because the system is stationary at the beginning)
Where:
m1 = mass of the astronaut
v1= velocity of the astronaut
m2= mass of the satellite
v2= velocity of the satellite
Replacing with the values given and solving:
86 kg (2.35m/s) = 360 kg v2
202.1 kgm/s=360kg v2
202.1kgm/s /360kg =v2
v2 = 0.56 m/s
Feel free to ask for more if needed or if you did not understand something.
Answer:
a) k = 120 N / m
, b) f = 0.851 Hz
, c) v = 1,069 m / s
, d) x = 0
, e) a = 5.71 m / s²
, f) x = 0.200 m
, g) Em = 2.4 J
, h) v = -1.01 m / s
Explanation:
a) Hooke's law is
F = k x
k = F / x
k = 24.0 / 0.200
k = 120 N / m
b) the angular velocity of the simple harmonic movement is
w = √ k / m
w = √ (120 / 4.2)
w = 5,345 rad / s
Angular velocity and frequency are related.
w = 2π f
f = w / 2π
f = 5.345 / 2π
f = 0.851 Hz
c) the equation that describes the movement is
x = A cos (wt + Ф)
As the body is released without initial velocity, Ф = 0
x = 0.2 cos wt
Speed is
v = dx / dt
v = -A w sin wt
The speed is maximum for sin wt = ±1
v = A w
v = 0.200 5.345
v = 1,069 m / s
d) when the function sin wt = -1 the function cos wt = 0, whereby the position for maximum speed is
x = A cos wt = 0
x = 0
e) the acceleration is
a = d²x / dt² = dv / dt
a = - Aw² cos wt
The acceleration is maximum when cos wt = ± 1
a = A w²
a = 0.2 5.345
a = 5.71 m / s²
f) the position for this acceleration is
x = A cos wt
x = A
x = 0.200 m
g) Mechanical energy is
Em = ½ k A²
Em = ½ 120 0.2²
Em = 2.4 J
h) the position is
x = 1/3 A
Let's calculate the time to reach this point
x = A cos wt
1/3 A = A cos 5.345t
t = 1 / w cos⁻¹(1/3)
The angles are in radians
t = 1.23 / 5,345
t = 0.2301 s
Speed is
v = -A w sin wt
v = -0.2 5.345 sin (5.345 0.2301)
v = -1.01 m / s
i) acceleration
a = -A w² sin wt
a = - 0.2 5.345² cos (5.345 0.2301)
a = -1.91 m / s²
Correct answer is Availability of soil minerals.
There are two types of limiting factors that affect plant population in a ecosystem. They are:
- Biotic
- Abiotic
Biotic factors includes food, diseases etc. Such as Invasive weed species, seed dispersal by wind, disease-causing fungal spores are examples of biotic limiting factor.
Abiotic factors include sunlight, temperature and chemical environment. The availability of soil mineral is an example of abiotic limiting factor. Growth of plant population depends on availability of soil minerals.
Momentum = mass x velocity
Momentum = 10.5 x 3
Momentum = 31.5 kgm/s
