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soldi70 [24.7K]
1 year ago
9

Part K Find the y-component of the stone's velocity when it is 8.00 m below your hand

Physics
1 answer:
Romashka-Z-Leto [24]1 year ago
4 0

The y-component of the stone's velocity when it is 8 m below the hand is 14.86 m / s

v² = u² + 2 a s

s = Displacement

u = Initial velocity

a = Acceleration

u = 8 m / s

s = 8 m

v² = 8² + 2 * 9.8 * 8

v² = 64 + 156.8

v = √ 220.8

v = 14.86 m / s

The equation used to solve the problem is an equation of motion. These equations are designed to locate an object in motion using components such as velocity, displacement, acceleration and time.

Therefore, the y-component of the stone's velocity is 14.86 m / s

To know more about Equations of motion

brainly.com/question/5955789

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A normal walking speed is around 2.0 m/s . how much time t does it take the box to reach this speed if it has the acceleration 5
creativ13 [48]

Given:

u(initial velocity)=0

a=5.54m/s^2

v(final velocity)=2 m/s

v=u +at

Where v is the final velocity.

u is the initial velocity

a is the acceleration.

t is the time

2=0+5.54t

t=2/5.54

t=0.36 sec


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3 years ago
What is the minimum amount of data points an experiment should gather?
nydimaria [60]

The answer is "Three".

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3 years ago
A charged particle moving along the x-axis enters a uniform magnetic field pointing along the z-axis. Because of an electric fie
Furkat [3]

Answer:

Explanation:

Let the charge particle have charge equal to +q .

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F = q ( v i x B k )  , ( velocity is along x direction and magnetic field is along z axis. )

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The force will be along - ve y - direction .

If we take charge as negative or - q

force due to electric field will be along - y axis .

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= +  Bqv j

magnetic force will be along  + y axis

So it is difficult to find out the nature of charge on the  particle from this experiment.

5 0
3 years ago
When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end
Sunny_sXe [5.5K]

1) 29.8 C

At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).

2) 6.2 C

The temperature change of the water is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

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Substituting into the formula,

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And the positive sign means that the temperature of the water has increased.

3) -40.6 C

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where

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Substituting into the formula,

\Delta T=29.8 C-70.4 C=-40.6 C

And the negative sign means the temperature of the metal has decreased.

5 0
3 years ago
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Answer:

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