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3 years ago

Write the charge balance for a solution that contains h , oh–, mg2 , hso4–, so42–, mg(hso4) , mg(oh) , na , and no3–.

1 answer:

5 0

A solution is when a solute is added to a water solvent. Since water is neutral, the charge of the said solution is dictated by the charge of the ion. This is the subscript of the element. If it is not stated, then we use the common ion form.

1. H: The charge for hydrogen ion is +1.
2. OH⁻: The charge is ⁻1.
3. Mg2: This ion has a charge of +2.
4. HSO₄⁻: -1
5. SO₄²⁻: -2
6. Mg(HSO₄): This is not an ion, but an undissociated compound. So, it has a neutral charge of 7.
7. Mg(OH): Neutral at pH 7
8. Na: Sodium ion has a charge of +1.
9. NO₃⁻: -1.

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Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=22.0g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, $\frac{12}{44}\times 22.0=6g$ of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = $\frac{0.5}{0.5}=1$

For Hydrogen = $\frac{1.0}{0.5}=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is $C_{1}H_{2}=CH_2$

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