Ask question

Ask question

All categories

2 years ago

14

1 You place a 28.95-g piece of gold in a 10-ml graduated cylinder. The level of the water rises 1.50 mL. What is the density of

gold?

1 answer:

shutvik [7]2 years ago

5 0

Answer:

What mass of silver will raise the level of the water in the graduated cylinder 1.50 mL? (Ans) 28.95 g / 1.50 mL = 19.3 g/mL (The gold's density)

You might be interested in

The first stage of aerobic respiration is a series of biochemical reactions called the Calvin cycle.

Marina CMI [18]

Answer:

The answer is indeed true

Explanation:

8 0

3 years ago

Examples of nitrogens unreactivity

REY [17]

WATCH OUT BUDDY:<span>reactivity....Spelling mistake.

ANSWER:
</span>For example<span>, "air" sometimes comes bubbling out of the ground near oil wells. Today ... For </span>example, nitric oxide combines with oxygen and water in the atmosphere to make nitric acid. When it ....Nitrogen's<span> role in the Oklahoma City bombing.</span>

8 0

3 years ago

How do I balance this equation?

gavmur [86]

Answer: place a 2 in front of NaNo3 on left side of equation while leaving the other blanks empty or you can place a 1 in those blanks

Explanation:

Step 1 count and write down the amount of each given element for both sides

Step 2 begin placing numbers (coefficients) to each side to balance

7 0

3 years ago

A substance has a volume of 10.0 cm3 and a mass of 89 grams. What is its density?

AlladinOne [14]

8.9 g/cm3 since density equals mass/volume or m/v you just divide 89 by 10 to get 8.9

4 0

3 years ago

Read 2 more answers

For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomas

Flauer [41]

Answer:

4.25% is the final concentration of phosphoric acid.

Explanation:

Initial concentration of phosphoric acid = $C_1=85\%=0.85$

Initial volume of phosphoric acid = $V_1=50 mL$

Final concentration of phosphoric acid = $C_2=?$

Final volume of phosphoric acid = $V_2=1 L=1000 mL$

( 1L = 1000 mL)

$C_1V_1=C_2V_2$

$C_2=\frac{C_1times V_1}{V_2}$

$=\frac{0.85\times 50 mL}{1000 mL}=0.0425=4.25%$

4.25% is the final concentration of phosphoric acid.

4 0

3 years ago