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3 years ago

A pyramid has a base are of 124in and a height of 25.2in what is the volume. of the pyramid?

Mathematics

1 answer:

anzhelika [568]3 years ago

8 0

Volume of a pyramid = 1/3 * height * area of the base

Here V = 1/3 * 124 * 25.2

= 1041.6 in^3 (answer)

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in this line of circles, the ratio of the red circles to blue circles is 1:3. how many more red circles would need to be added t

Tems11 [23]

Answer:

Step-by-step explanation:

If we assume that initially

Number of red counter is 1

Number of blue counter is 3

Now to make ratio reverse you need to add 8 more red counters so that ratio becomes

9:3=3:1

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3 years ago

F(x)=4x squared −7x+7, Find f(2)

Lana71 [14]

Answer: 9

Step-by-step explanation:

4x²-7x+7 f(2)=4*(2)^2-7(2)+7=16-14+7=9

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3 years ago

1. Thales, an ancient Greek mathematician, and philosopher used certain triangles to find the height of unknown objects. He wait

charle [14.2K]

An equilateral triangle.

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3 years ago

Simplify the following expression <br>9/20 + 5/12

Artyom0805 [142]

<em>9/20+5/12=14/32/2 equals a over all 7/16</em>

4 0

3 years ago

Read 2 more answers

Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff

liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places. The formula for Newton's Method is

$x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }$

If our function is

$f(x)=x^5+x-6$

then the first derivative is

$f'(x)=5x^4+1$

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2. I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0

3 years ago