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2 years ago

Describe how glacial erosion influenced the topography of Ohio.

1 answer:

4 0

During the past two million years, glaciers have shaped and reshaped the surface of Ohio several times. These continental masses of ice affected as much as two-thirds of the state. Moving from the north and northwest, glaciers have scraped and flattened the landscape. Often more than a mile thick, they smoothed existing hills and filled valleys with enormous amounts of rocks, gravel, and smaller particles. Through these actions, glaciers have had a very important impact on the agriculture of Ohio. Their activity has been felt in two noticeable ways: shaping the ground upon which people work and build, and forming the soils that cover that ground.

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Label each of the following changes as a physical change or chemical change. Give evidence to support your answer.

SVEN [57.7K]

Answer:

A catalytic converter changes nitrogen dioxide to nitrogen gas and oxygen gas is a chemical change.

Explanation:

Hello.

In this case, since physical changes do not modify the molecular composition and structure of the material undergoing it whereas the chemical change does, for catalytic converters we should know they promote chemical reaction in which the composition is changed; for instance, for the given example, the following chemical reaction is the evidence:

$2NO_2\rightarrow N_2+O_2$

As you can see, nitrogen and oxygen are no longer bonded but separated by themselves, therefore, this is a chemical change.

Best regards.

3 0

2 years ago

Roman mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 16% acid solution. Find the number of lit

inysia [295]

Let the 8% solution be A, the 20% solution be B and the final solution be C.

C = A + B
C = 12 + B

0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters

C = 12 + 24
C = 36 Liters

3 0

3 years ago

Nitrogen gas and oxygen gas react according to the following equation: Energy + N2(g) + O2(g) Double arrow yields 2NO(g) Nitroge

Ann [662]

- increasing the concentration of N₂
- increasing the concentration of O₂
- decreasing the concentration of NO
- increasing the temperature

:)

7 0

3 years ago

Can somebody please help me!!!

pogonyaev

Explanation:

Student A would be introducing more error. While student B is subtracting the actual filter paper used in the experiment, Student A is using the mass of a different filter paper, which may have a slightly different mass than the filter paper that was used. To avoid having to aacount for this, or introducing such an error, follow Student B in weighing the filter paper before adding the sand.

I hope this helps.

5 0

2 years ago

Given the 1H and 13C data below, which isomers of C8H11N fit the spectral data? 13C NMR: δ 17.2, 20.4, 115.1, 122.4, 137.3, 127.

iogann1982 [59]

Complete Question

The complete question is shown on the first , second , third and fourth

Answer:

The compound that fit the spectra data are compound B, E and H as shown in the question

Explanation:

From the question we are given that the 13C NMR data is

13C $NMR: 17.2,20.4,115.1,122.4,137.3,127.6,131.1,142.1$ pmm

From the spectral diagram on the question we can see that the signal at 17.2 ppm and 20.4 ppm indicates the presence of two different $sp^{3}$ carbon atoms.

Also the signals at 115.1 , 122.4 , 137.3, 127.6,131.1,142.1 ppm indicates the molecule with six different $sp^{2}$ carbon atoms.

Thus , the compound with two different $sp^{3}$ carbon atoms and six different $sp^{2}$ carbon atoms are shown on the third uploaded image

Now let us take a look at the 1H NMR as follows

For NMR spectra the integration values are in the ration 1.99:1.00:2.19: 5.93

Now we can look at this above ratio like this 2:1:2:6 by reduction

Hence the relative number of proton is in the ratio of 2H: 1H: 2H: 6H

2H at 6-7 ppm and 1H at 6-7 ppm are due to the presence of three aromatic proton which are present on the benzene ring.

2H at 3.5 ppm are due to proton in amino group $NH_{2}$ protons.

6H gives two signals at 2.2 ppm due to the presence of the two $CH_{3}$ protons

The compound A is not matched with 1 H NMR spectra, thus remove the compound A .The other compounds are B,E,F

Thus ,the compound with the proton in the ratio 2H : 1H :2H : 6H are shown on the fourth uploaded image

Hence the compounds with the given NMR spectra are B,E and H

4 0

2 years ago