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zvonat [6]
3 years ago
6

The table above represents what type of function?

Mathematics
2 answers:
exis [7]3 years ago
7 0

Answer:

A?? because I think it's not linear because it's not proportional

kupik [55]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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HELP I NEED HELP ASAP
Ira Lisetskai [31]

Answer:

B

Step-by-step explanation:

8 0
2 years ago
What is the following product?
Aneli [31]
Your correct it’s the first one
4 0
2 years ago
Find and interpret the mean absolute deviation of the data. Round your answers to the nearest tenth. If necessary 101.5 98.7 95.
lesya692 [45]

Answer:

\bar X = 100.4

And we can calculate the deviations from each value like this:

|101.5-100.4 |=1.1

|98.7-100.4 |=1.7

|95.4-100.4 |=5.0

|92.3-100.4 |=8.1

|109.8-100.4 |=9.4

|104.7-100.4|=4.3

And the mean absolute deviation would be:

MAD =\frac{1.1+1.7+5.0+8.1+9.4+4.3}{6}= 4.93

Step-by-step explanation:

For this case we have the following dataset given:

101.5 98.7 95.4 92.3 109.8 104.7

We can calculate the mean with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = 100.4

And we can calculate the deviations from each value like this:

|101.5-100.4 |=1.1

|98.7-100.4 |=1.7

|95.4-100.4 |=5.0

|92.3-100.4 |=8.1

|109.8-100.4 |=9.4

|104.7-100.4|=4.3

And the mean absolute deviation would be:

MAD =\frac{1.1+1.7+5.0+8.1+9.4+4.3}{6}= 4.93

8 0
3 years ago
B) y = 3 = 2х<br><br> Is this relation linear or non-linear? Explain why.
Alika [10]

Answer:

I think you meant: y=3+2x, in that case, this is a linear answer

Step-by-step explanation:

Non- linear would look like this: K=2/3

Linear would look like this: Y=4x+7

Why:

It all comes to what is proportional and what is not.

Hoped this helped!

3 0
3 years ago
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
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