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3 years ago

What is the frequency of an electromagnetic wave that has a wavelength of

Chemistry

1 answer:

Korolek [52]3 years ago

3 0

➡ ANSWER

☑ C. 3.5 105 Hz

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Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh

Aliun [14]

Answer:

1.60.

Explanation:

The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.

The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

∵ pH = - log[H⁺]

∴ pH = - log[H⁺] = - log(0.025) = 1.602 ≅ 1.60.

5 0

4 years ago

Which do all cells need in order to function?

vazorg [7]

Oxygen, should be correct
sometimes we use and need mandatory

8 0

3 years ago

Lithium hydroxide is used in alkaline batteries. Calculate the molarity of a solution prepared by dissolving 1.495 moles of LiOH

weeeeeb [17]

Answer:1)1.99 M

Explanation:

Molarity is given as = moles solute/Liter solution

The solute which is LiOH is already given in moles as 1.495 moles

Given that solution is 750 mL, we convert to liters.

Liters of the solution= mL of the solution x (1 L/1000 mL)

750 mL x (1 L/1000 mL)

0.75 L

Molarity = moles solute/Liter solution

Molarity = 1.495 moles of LiOH/0.75 L of solution

Molarity = 1.99M

The molarity of this solution is 1.99M (moles per liter).

5 0

3 years ago

NO(g)+O3(g)⇌NO2(g)+O2(g) The reaction is first order in O3 and second order overall. What is the rate law? View Available Hint(s

Ivanshal [37]

NO(g)+O3(g)⇌NO2(g)+O2(g)

3 0

3 years ago

Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ

Ahat [919]

Answer: The Gibbs free energy of the reaction is 21.32 kJ/mol

Explanation:

The chemical equation follows:

$\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln K_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = $37^oC=[273+37]K=310K$

$K_{eq}$ = Ratio of concentration of products and reactants = $\frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}$

$\text{[Oxaloacetate]}=0.130mM$

$[NADH]=2.0\times 10^2mM$

$\text{[Malate]}=1.37mM$

$[NAD^+]=490mM$

Putting values in above expression, we get:

$\Delta G=29700J/mol+(8.314J/K.mol\times 310K\times \ln (\frac{0.130\times 2.0\times 10^2}{1.37\times 490}))\\\\\Delta G=21320.7J/mol=21.32kJ/mol$

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol

4 0

3 years ago