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Kitty [74]
3 years ago
13

What is the frequency of an electromagnetic wave that has a wavelength of

Chemistry
1 answer:
Korolek [52]3 years ago
3 0

➡ ANSWER

☑ <em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u>3.5 105</u></em><em><u> </u></em><em><u>Hz</u></em>

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A group of two or more atoms held together by mutually shared electrons are called ________.
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The answer is _molecule_.

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The storage method used for radioactive wastes generated from fission nuclear reactors must be designed to last for how long?
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The right answer is centuries

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A sample of carbon dioxide gas (CO2) contains 8.551 x 1025 molecules. How many moles of carbon dioxide does this represent?
ozzi

Answer:

142.0 moles CO₂

Explanation:

To answer this question, we first need to know what a mole is. A mole represents 6.022 \cdot 10^{23} of something, and in this case, that something is molecules.

So, to convert 8.551 \cdot 10^{25} molecules into moles, we need to use the conversion factor  1=\frac{6.022\cdot 10^{23} \text{molecules} }{ \text{1 mole}}.

Doing so (using dimensional analysis) gives us:

8.551 \cdot 10^{25} \text{ molecules } \cdot  \frac{\text{1 mole}}{ 6.022\cdot 10^{23} \text{ molecules} } = \frac{8.551 \cdot 10^{25}}{ 6.022\cdot 10^{23}} \text{ moles CO}_2 = \\ \\ 141.996 \text{ moles CO}_2 = \boxed{142.0 \text{ moles CO}_2 }

8 0
3 years ago
500mL of air are trapped in a tube over mercury at 25°C. It is found that, after six
Papessa [141]

Answer:

The new temperature is 19.072 K.

Explanation:

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure. This law says that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules.

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Assuming that a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment varies up to a volume of gas V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 500 mL
  • T1= 25 C= 298 K
  • V2= 32 mL
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Replacing:

\frac{500 mL}{298 K}=\frac{32 mL}{T2}

Solving:

T2=32 mL*\frac{298 K}{500 mL}

T2= 19.072 K

<u><em>The new temperature is 19.072 K.</em></u>

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3 years ago
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