All i know that we are HOOman
B.
Isotopes is an atom has same number of electrons and protons but different number of neutron.
<span>Divide each % value by respective atomic mass
Mn = 63.0/54.94 = 1.1467
O = 37/16 =2.3125
Divide by smaller value
Mn = 1
O = 2.3125/1.1467 = 2 Empirical formula = MnO2</span>
Answer : The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation :
Standard formation of reaction : It is a chemical reaction that forms one mole of a substance from its constituent elements in their standard states.
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of
will be,

The intermediate balanced chemical reaction will be,
(1)

(2)

(3)

Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, we get :
(1)

(2)

(3)

The expression for enthalpy of formation of
will be,



Therefore, the standard enthalpy of formation of methanol is, -238.7 kJ/mole
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