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Mila [183]
3 years ago
12

How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with

1.15 liters of a 2.75 molar potassium chromate K2CrO4 solution? Pb(NO3)2 + K2CrO4 PbCrO4 + 2KNO3 108 g 681 g 639 g 362
Chemistry
1 answer:
fgiga [73]3 years ago
4 0
I know that the answer is 639 g
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The concentration of the HCl solution is 0.047 M.

Explanation:

Data given about acid and base:

volume of acid Vacid = 46.9 ml

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To know the concentration of the acid in this reaction, the formula used in titration  is used. It is

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the formula is rewritten as:

Macid = \frac{Mbase X Vbase}{Vacid}

putting the values in the equation:

Macid = \frac{0.135 X 16.4}{46.9}

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