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Mila [183]
3 years ago
12

How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with

1.15 liters of a 2.75 molar potassium chromate K2CrO4 solution? Pb(NO3)2 + K2CrO4 PbCrO4 + 2KNO3 108 g 681 g 639 g 362
Chemistry
1 answer:
fgiga [73]3 years ago
4 0
I know that the answer is 639 g
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