1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kompoz [17]
3 years ago
12

A company that makes shampoo wants to test whether the average amount of shampoo per bottle is 16 ounces. the standard deviation

is known to be 0.20 ounces. assuming that the hypothesis test is to be performed using 0.10 level of significance and a random sample of n = 64 bottles, how large could the sample mean be before they would reject the null hypothesis?
Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0
<span>Answer: n=64 is large enough to use a z-test. The two-tailed 90% confidence interval (5% in each tail) is pop. mean +/- 1.64 (s.d. / sqrt(n) ) = 16 +/- 1.64 * 0.2/8 oz = [15.959, 16.041]oz m</span>
You might be interested in
PLEASE HELP
Eva8 [605]

Answer: 51 Children and 36 Adults.

Step-by-step explanation: Let's call x the number of children admitted and call z the number of adults admitted.

We know that x+z= 87

We also know that 3.25x+3.5z= 291.75.

We want to find the value of x and z. Then we solve the system of equations:

Multiply the first equation by -3.5 and add it to the second equation:

-3.5x-3.5z= -304.5

3.25x+3.5z= 291.75

-----------------------------------------------------------------------------------------------------------------

-0.25x=-12.75

x= -42.75 ÷ -0.25

x=51

----------------------------------------------------------------------------------------------------------------

Now we substitute the value of x in the first equation and solve for the variable z

51+z=87

z=87-51

z= 36

Omg took me like 10 minutes to calculate would appreciate brainliest. Have a wonderful day.

6 0
3 years ago
Patrick says that .500 is greater than .50 and .5 is he correct?
Dafna1 [17]
No he is not  .500, .50 and .5 are all the same number.

8 0
3 years ago
Calculate dy/dxif y = 4x3 + 3x2 + 2.
Elena-2011 [213]
The answer is
 <span>A. 12x2 + 6x

solution 
</span><span>y = 4x3 + 3x2 + 2
</span><span>y'(x) = 12x^2 + 6x


</span>
7 0
3 years ago
In a certain​ country, the true probability of a baby being a girl is 0.469. Among the next seven randomly selected births in th
-BARSIC- [3]

Answer:

The probability is 0.995 ( approx ).

Step-by-step explanation:

Let X represents the event of baby girl,

The probability of a baby being a girl is, p = 0.469,

So, the probability of a baby who is not a girl is, q = 1 - 0.469 = 0.531,

Also, the total number of experiment, n = 7

Thus, by the binomial distribution formula,

P(x)=^nC_x(p)^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

The probability that all babies are girl or there is no baby boy,

P(X=7)=^7C_7(0.469)^7(0.531)^{7-7}

=0.00499125661758

Hence, the probability that at least one of them is a boy​ = 1 - P(X=7)

= 1 - 0.00499125661758

= 0.995008743382

≈ 0.995

8 0
3 years ago
If backpack is discounted 10% ib sale for $37.80 what is the original price
taurus [48]

the answer is $34. 36 if I understood your question correctly.
8 0
3 years ago
Other questions:
  • U - 5.3 = 3.99 gxmdksgsjdkd
    12·1 answer
  • 3/5 of jills 30 page photo album is full. She wants to set aside 1/4 of the pages that are left for photos of her vacation. How
    6·1 answer
  • I need to know 37-45 and show work
    6·2 answers
  • Find x using Pythagorean theorem​
    9·1 answer
  • What rational number represents a drop of ​ 4 1/4 ​ in.?
    5·1 answer
  • The ratio of the number of text messages sent by Diego to the number of text messages sent by his sister is 3 to 4. Diego sent 1
    12·1 answer
  • Which has a smaller area, Figure A, or Figure B?
    15·1 answer
  • LOOK AT THE PIC BELOW
    13·2 answers
  • I have so many points help me
    8·1 answer
  • Write the possible range of the measurement: 220 km ± 5%.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!