Answer:
302 kj heat is released by lowering the temperature
Answer is: mass of acetone is 22.51 grams.:
V(acetone - C₃H₆O) = 28.66 mL; volume.
d(acetone) = 0.7857 g/mL; density.
m(acetone) = V(acetone) · d(acetone).
m(acetone) = 28.66 mL · 0.7857 g/mL.
m(acetone) = 22.51 g; mass.
Acetone<span> or </span>propanone is the <span>colorless, volatile, flammable </span>organic compound (ketone).
In writing the formula for a salt the symbol of the cation is first then the anion is written second .
We have to get the amount of nitrogen to be consumed to get 0.75 moles of ammonia.
The amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is: 10.5 grams.
Ammonia (NH₃) can be prepared from nitrogen (N₂) as per following balanced chemical reaction-
N₂ (g) + 3H₂ (g) ⇄ 2NH₃ (g)
According to the above reaction, to prepare 2 moles of ammonia, one mole of nitrogen is required. Hence, to prepare 0.75 moles of ammonia, moles = 0.375 moles of nitrogen is required.
Molar mass of nitrogen is 28 grams, i.e, mass of one mole of nitrogen is 28 grams, so mass of 0.375 moles of nitrogen is 0.375 X 28 grams=10.5 grams of nitrogen.
Therefore, the amount of nitrogen (in grams) required to prepare 0.75 moles of ammonia is 10.5 grams.
The answer is A() nitrogen-fixing bacteria
it converts nitrogen it kind of says it in the name