We calculate the entropy of an ideal gas follows:
<span>For an isothermal compression, change in internal energy is equal to zero.</span>
<span>Thus, the heat added to the gas is equal to the work done on the gas which is given as 1750 J.</span>
<span>Entropy would be 1750/301 = 5.81 J/K </span>
The answer is B milliliter
The equilibrium constant for the reaction is 0.00662
Explanation:
The balanced chemical equation is :
2NO2(g)⇌2NO(g)+O2(g
At t=t 1-2x ⇔ 2x + x moles
The ideal gas law equation will be used here
PV=nRT
here n=
=
= density
P =
density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm
putting the values in reaction
0.75 = 
M = 34.61
to calculate the Kc
Kc=![\frac{ [NO] [O2]}{NO2}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5BNO%5D%20%5BO2%5D%7D%7BNO2%7D)
x M NO2 +
M NO+
M O2
Putting the values as molecular weight of NO2, NO,O2

34.61= 
x= 0.33
Kc= 
putting the values in the above equation
Kc = 0.00662
<span> A compound <span>lens microscope. </span></span>
The answer you are looking for is 4.