Answer:
30 moles of water will produced.
Explanation:
Given data:
Number of moles of O₂ react = 15 mol
Number of moles of water formed = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Now we will compare the moles of water with oxygen.
O₂ : H₂O
1 : 2
15 : 2×15 = 30 mol
30 moles of water will produced.
Answer:
E) 0.90
Explanation:
In TLC (Thin-Layer-Chromatography) retention factor RF is defined as the ratio between distance of the sample and the solvent front. RF is very important in chemistry to know the composition of any sample by comparison.
In the problem, as the sample has a distance of 0,20cm from the solvent front, the distance of the sample is:
2,0cm - 0,20 cm =<em> 1,8 cm</em>. Thus, RF is:
RF = 1,8cm / 2,0cm = 0,90
<em>E) 0,90</em>
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I hope it helps!
B, you can see there are 2 F atoms on each side of the equation
Answer:
<em>a)C4H5N2O</em>
<em>b)C12H22O11</em>
<em>c)HO2</em>
<em>d)CH2O</em>
<em>e)C3H4O3</em>
Explan ation:
To obtain th e empirical formul a from the molecular for mula you have to divide the subscripts by the largest whole number you can, that provide you a whole number for each one subscripts:
I am assuming that the problem ask for the pressure in
the system. To be able to calculate this, we first assume that the system acts
like an ideal gas, then we can use the ideal gas equation to find for pressure
P.
P V = n R T
where,
P = Pressure (unknown)
V = 0.17 m^3
n = moles of lng / methane
R = gas constant = 8.314 Pa m^3 / mol K
T = 200 K
We find for the moles of lng. Molar mass of methane = 16
kg / kmol
n = 55 kg / 16 kg / kmol
n = 3.44 kmol CH4 = 3440 mol
Substituting all the values to the ideal gas equation:
P = 3440 mol * (8.314 Pa m^3 / mol K) * 200 K / 0.17 m^3
P = 33,647,247 Pa
<span>P = 33.6 MPa</span>
