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ValentinkaMS [17]
3 years ago
7

Three of the primary components of air are

Chemistry
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

174.402 Torr is the partial pressure of oxygen gas.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

P_T=p_{1}+p_{2}+p_{3}...p_{n}

where,

P_T = Total pressure

p_{1} = partial pressure of gas-1

p_{2} = partial pressure of gas-2

p_{3} = partial pressure of gas-3

p_{n} = partial pressure of nth gas in the mixture

We have:

P_T= 1 atm = 760 Torr

p_{CO_2}=0.285 Torr

p_{N_2}=585.313 Torr

p_{O_2}=?

Now put all the given values is expression, we get the partial pressure of the O_2 gas.

P_T=p_{CO_2}+p_{N_2}+p_{O_2}

760 Torr=0.285 Torr+585.313 Torr+p_{O_2}

p_{O_2}=174.402 Torr

174.402 Torr is the partial pressure of oxygen gas.

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When 2 moles of Na(s) react with H2O(l) to form NaOH(aq) and H2(g) according to the following equation, 369 kJ of energy are evo
enot [183]

Answer:

Exothermic

q = -8.03 kJ/g

Explanation:

<em>When 2 moles of Na(s) react with H₂O(l) to form NaOH(aq) and H₂(g) according to the following equation, 369 kJ of energy are evolved.</em>

The thermochemical equation is:

2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g)    ΔH = -369 kJ

Since the energy is evolved, the reaction is exothermic, which is why the enthalpy of the reaction (ΔH) is negative.

The heat released (q) per gram of Na(s) is (molar mass 22.98 g/mol):

\frac{-369kJ}{2molNa} .\frac{1molNa}{22.98gNa} =-8.03kJ/g

4 0
3 years ago
Mass in grams of 6.023×1023 atom of Ca​
Mademuasel [1]

Answer:

\boxed {\boxed {\sf 40.08 \ grams}}

Explanation:

First, find the molar mass of calcium (Ca). This can be found on the Periodic Table.

  • 40.08 g/mol

Next, find the number of moles.

Avogadro's Number tells us the number of atoms in one mole.

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Therefore, there are 6.023*10²³ atoms in 1 mole.

We have 6.023*10²³ atoms of calcium, so it must also be 1 mole of calcium.

Finally, find the mass. Set up a proportion using the molar mass of calcium.

1 \ mol \ Ca * \frac{40.09 \ g}{1 \ mol \ Ca}

Multiply. The moles (mol Ca) will cancel.

1 * 40.08 \ g

40.08 \ g

There are <u>40.08 grams </u>in 6.023*10²³ atoms of calcium.

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types include, in order of increasing frequency, radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.

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