Answer:
Fatty acids
Explanation:
Acetyl coA is a compound vital for the process of cellular respiration in the mitochondria. It is the starting material of the kreb's cycle or TCA cycle, which takes place in the mitochondria. During the metabolism of glucose (glycolysis), a molecule called PYRUVATE is first synthesized before becoming acetyl coA in the mitochondrion.
However, the metabolism of FATTY ACIDS (monomers of lipids) directly gives rise to acetyl coA without first becoming pyruvate. The fatty acids molecule undergo Beta- oxidation to produce acetyl coA, which enters the TCA cycle to continue cellular respiration.
Delta E= R[1/n^2 (initial) - 1/n^2 (final) ]
so transition n=3 to n=1 will emit more energy
The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
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