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IrinaVladis [17]
4 years ago
5

A student measures the mass of a 6.0 cm3 block of brown sugar to be 10.0 g. What is the density of the brown sugar?

Chemistry
2 answers:
Alex17521 [72]4 years ago
8 0

Answer:

1.67g/cm3

Explanation:

The formula for density is d=\frac{m}{v} . The m variable stands for mass and the v variable stands for volume.

The mass of the brown sugar is 10.0g and the volume is 6.0cm3, so we can plug those values into the equation.

d=\frac{10g}{6cm^{3} }

d=1.67\frac{g}{cm^{3} }

Rounded to 3 significant figures, the density of the block of brown sugar is 1.67 g/cm3. If the mass is in grams and the volume is in cm3, the unit for the final answer is \frac{g}{cm^{3} } (grams per centimetres cubed).

Oksi-84 [34.3K]4 years ago
6 0

Answer:

16g

Explanation:

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What is the temperature (°C) of 1.75 g of O2 gas occupying 3.10 L at 1.00 atm? Enter your answer in the box provided.
Ierofanga [76]

Answer:

691.29 K or 418.14 °C

Explanation:

Hello, at first the moles of oxygen gas are required:

n_{O_2}=1.75 g * \frac{1mol O_2}{32 g O_2} =0.0547 mol

Now, based on the ideal gas equation, we solve for the temperature:

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5 0
4 years ago
a lead ball has a mass of 5.910 g and a diameter or 10.0 mm what is the density of lead in grams per cubic centimeters .The volu
storchak [24]

Answer:

11.3 g/cm³

Explanation:

Data Given:

Diameter of lead ball = 10.0 mm

Convert mm to cubic centimeter (cm³)

1 mm = 0.1 cm

So,

10.0 mm = 10.0 x 0.1 = 1 cm

mass of lead ball = 5.910 g

density of of lead ball =?

Solution:

To find density formula will be used

            d = m/V ...........(1)

where

d = density

m = mass

V = volume

So,

To find the density of the lead ball (sphere), first we have to find volume of the ball.

To find volume of the ball following formula will be used

                   V = 4 . π . r³/ 3 ..............(2)

where

π = 3.14

r = radius

So,

  • r = D/2

as

  • D = 1 cm

So, radius will be

     r = 1 cm / 2

     r = 0.5 cm

Now put values in formula 2

                   V = (4)(3.14)(0.5cm)³/ 3

                   V = (12.56)(0.125 cm³) /3

                   V = 1.57 cm³/3

                   V = 0.523 cm³

So, the volume of the lead ball is 0.523 cm³

Now put values in equation 1

                     d = m/V

                      d = 5.910 g / 0.523 cm³

                      d = 11.3 g/cm³

Density of the lead ball = 11.3 g/cm³

7 0
4 years ago
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