Supposing we begin with n=1, the first few terms of this arith sequence are
5, 1, -3, -7, and so on. 4 is the common difference.

This means that a field of those dimensions would not be the required length of a minimum of 110 feet.
Answer:
(1/27) in^3
Step-by-step explanation:
"sides" is inappropriate here. You meant "a cube with three edges each 1/3 inch long."
V of cube: V = s^3, where s: side length
Here, V = (1/3 in)^3 = (1/27) in^3
Note: all cubes have 6 (six) sides, including this one with 6 1/3 in sides.
Find the percent of the circle
r=radius of circle
then r=1/2 of the diagonal of the square
use some pythagoran theorme
45,45,90 triangle
(r√2)/2=1/2 of a side
r√2 is one side
square it
2r²=square
area of circle is pir²
percent it is is
square/circle=
(2r²)/(pir²)=
2/pi= about
0.636
about 64% that it is in the square
<span>A) Participation in the spring league is increasing more than twice as fast as participation in the fall league.
this is what i believe is the answer. Parcipatation raises by 11 for spring and 3 for fall, and 11 is more than twice 3. i hope this helps! :D</span>