Answer:
765.95 grams.
Explanation:
2 moles of KClO3 produce 3 moles of oxygen.
Using molar masses:
2 * 122.545 g of KCLO3 produces 47.997 grams of oxygen.
47.997 g O2 is produced from 245.09 g KCLO3
150 g .......................................... 150 * 245.09 / 47.997
= 765.95 grams.
Answer:
A) The reaction absorbs energy
This is because the before reading show the temperature of 20°C whereas the after reading show the temperature of 13 °C
<h3>
<em><u>MORE</u></em><em><u> </u></em><em><u>TO</u></em><em><u> </u></em><em><u>KNOW</u></em><em><u> </u></em></h3>
- The reaction in which energy is absorbed is known as <em><u>Endothermic</u></em><em><u> </u></em><em><u>reaction</u></em><em><u> </u></em>
- The reaction in which energy is releases is known <em><u>Exothermic</u></em><em><u> </u></em><em><u>reaction</u></em>
As the size of a star increases, luminosity increases. If you think about it, a larger star has more surface area. That increased surface area allows more light and energy to be given off. Temperature also affects a star's luminosity.
Answer:
NH3
Explanation:
In solution, they are in equilibrium. NH4+ acts as a bronsted Lowry acid and donates an H to become NH3, and NH3 acts as a bronsted lowry base and accepts an H. In this pair, NH3 is a weak base, which gets its basic character due to the presence of lone pair of nitrogen and its ability to donate it.
First let us compute for the number of moles of butane
(molar mass = 58.12 g/mol)
number of moles = 145 g / (58.12 g/mol) = 2.49 mol
<span>We use the ideal
gas equation to calculate the volume:</span>
<span> V = n R T / P</span>
V = 2.49 mol * 62.36367 L torr / mol K * 308.15 K / 745
torr
<span>V = 64.35 L</span>