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Tpy6a [65]
2 years ago
11

For which of the following processes would you expect there to be an increase in entropy? Ag+(aq) + Cl-(aq) AgCl(s) H2O(g) H2O(l

) CaBr2(s) Ca+2(aq) + 2Br- (aq) CO2(g) CO2(s) N2(g) + 3F2(g) 2NF3(g)
Chemistry
2 answers:
Scorpion4ik [409]2 years ago
7 0

Answer: CaBr_2(s)\rightarrow Ca^{2+}(aq)+2Br^-(aq)

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

1. Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

The fast moving ions are converting to solid product, thus the entropy decreases.

2. H_2O(g)\rightarrow H_2O(l)

The fast moving gas is converting to liquid product, thus the entropy decreases.

3. CaBr_2(s)\rightarrow Ca^{2+}(aq)+2Br^-(aq)

The energy is absorbed by the reactants and the solid reactants are converting to fast moving ions, thus the entropy increases.

4. CO_2(g)\rightarrow CO_2(s)

The fast moving gas is converting to solid product, thus the entropy decreases.

5. N_2(g)+3F_2(g)\rightarrow 2NF_3(g)

4 moles of gas is converting to 2 moles of gaseous product , thus the entropy decreases.

Lyrx [107]2 years ago
6 0
CaBr₂(s) → Ca⁺²(aq) + 2Br⁻ (aq)     ΔS>0
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natka813 [3]

The given question incomplete, the complete question is:

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide (Al,03) dissolved in molten cryolite (Na, Alts).re in the reduction of the Al, o, to pure aluminum. Suppose a current of 1800. A is passed through a Hall-Heroult cell for 37.0 seconds. Calculate the mass of pure aluminum produced Be sure your answer has a unit symbol and the correct number of significant digits.

Answer:

The correct answer is 6.2114 grams.

Explanation:

Based on the given question, the value of current or I have given is 1800 amperes, the time given is 37 seconds, and there is a need to find the mass of the pure aluminum generated in the process. Mass or weight can be determined by using Faraday's first law equation, that is, w = MIt/nF.  

Here, M is the atomic mass, w is the weight of the substance deposited, t is time, I is current, n is the number of moles of the electron, and F is the Faraday's constant, which is 96500 C. In the process mentioned in the question, aluminum oxide is reduced to give rise to pure aluminum, and in the process 3 electrons are gained. So, the value of n will be 3. The M or the atomic mass of Al is 27 gm per mole. Now putting the values in the equation we get,  

w = 27*1800*37 / 3*96500

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7 0
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Answer:

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