Q1: Gases diffuse easily through amorphous or porous solids.
Q2:All changes in phase are called change in state of matter.
Answer:
Explanation:
Gases diffuse easily through amorphous or porous solids. Usually solids are densely packed with no space. But porous solids can help in diffuse gas into them. Due to the vacancy present in these solids, gas can easily diffuse through these types of solids.
Similarly, the phase changes lead to change in the state of matter. As the basic of change in phase leads to change in its state from solid to liquid or from liquid to gas or vice versa. So change in state of matter will occur in any change in phase.
Answer:
19.9 mol
Explanation:
Use <em>Avogadro’s number</em> to convert formula units of CaI₂ to moles of CaI₂.
1 mol CaI₂ ≡ 6.022 × 10²³ formula units CaI₂
Moles of CaI₂ = 1.20 × 10²⁵ × (1 /6.022 × 10²³)
Moles of CaI₂ = 19.9 mol
The molarity of the NaOH solution is 0.03 M
We'll begin by calculating the mole of the KHP
- Mass = 0.212 g
- Molar mass = 204.22 g/mol
- Mole of KHP =?
Mole = mass /molar mass
Mole of KHP = 0.212 / 204.22
Mole of KHP = 0.001 mole
Next, we shall determine the molarity of the KHP solution
- Mole of KHP = 0.001 mole
- Volume = 50 mL = 50/1000 = 0.05 L
- Molarity of KHP =?
Molarity = mole / Volume
Molarity of KHP = 0.001 / 0.05
Molarity of KHP = 0.02 M
Finally , we shall determine the molarity of the NaOH solution
KHP + NaOH —> NaPK + H₂O
From the balanced equation above,
- The mole ratio of the acid, KHP (nA) = 1
- The mole ratio of base, NaOH (nB) = 1
From the question given above, the following data were obtained:
- Volume of acid, KHP (Va) = 50 mL
- Molarity of acid, KHP (Ma) = 0.02 M.
- Volume of base, NaOH (Vb) = 35 mL
- Molarity of base, NaOH (Mb) =?
MaVa / MbVb = nA / nB
(0.02 × 50) / (Mb × 35) = 1
1 / (Mb × 35) = 1
Cross multiply
Mb × 35 = 1
Divide both side by 35
Mb = 1 / 35
Mb = 0.03 M
Thus, the molarity of the NaOH solution is 0.03 M
Complete question:
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Learn more about titration: brainly.com/question/25866669
Answer:

Explanation:
Graham’s Law applies to the effusion of gases:
The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

If you have two gases, the ratio of their rates of effusion is

The time for diffusion is inversely proportional to the rate.

Let CO₂ be Gas 1 and O₂ be Gas 2
Data:
M₁ = 44.01
M₂ = 32.00
Calculation
