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Brrunno [24]
4 years ago
10

How does the electric force between two charged particles change if one

Physics
1 answer:
ExtremeBDS [4]4 years ago
7 0

Answer:

brainly.com/question/11848211

^ Similar/same question as yours!

The pressure between two costs is proportional to the product of the charges.

If solely one of the expenses is decreased by way of a element of 3, then the pressure is decreased with the aid of a thing of 3.

If each prices are reduced by a thing of 3, then the pressure is reduced via a issue of 9.

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What is the frequency of a radio wave with an energy of 3.686 × 10−24 j/photon?answer in units of hz?
Makovka662 [10]

To solve this problem, we have to use the formula:

E = h f

where E is total energy, h is Plancks constant 6.626x10^-34 J s, f is frequency

 

f = E / h

f = 3.686 × 10−24 J / (6.626x10^-34 J s)

<span>f = 5.56 x 10^9 Hz</span>

4 0
3 years ago
Anna and Jon sit on a seesaw. Anna has a mass of 60 kg and sits 2 m from the center. Jon has a mass of 70 kg. How far from the c
Ronch [10]

Answer:

dJ = 1.7 m

Explanation:

The Equation of the Balancing the moments in the center of the seesaw  is like this:

∑Mo = 0

Mo = F*d

Where:

∑Mo : Algebraic sum of moments in the center(o) of the balance

Mo : moment in the o point ( N*m)

F  : Force ( N)

d  : distancia of the force to the the o point  ( N*m)

Data

mA = 60 kg : mass of the Anna

mJ = 70 kg :  mass of theJon

dA = 2 m : Distance from Anna to the center of the seesaw

g: acceleration due to gravity

Calculation of the distance from Jon to the center of the seesaw  (dJ)

∑Mo = 0   WA : Ana's weight   , WJ : Jon's weight

W = m*g

(WA)(dA) - (WJ) (dJ) = 0

(mA*g)(dA) - (mJ*g)(dJ) = 0

We divide by g the equation:

(mA)(dA) - (mJ)(dJ)= 0

(mA)(dA) = (mJ)(dJ)

d_{J} = \frac{m_{A} *d_{A}}{m_{J}}

d_{J} = \frac{60 kg *2 m}{70 kg}

dJ = 1.7 m

5 0
3 years ago
If someone is moving at a constant speed of 100 km/h and accelerate to 120km /h in 10 s what is the acceleration
Alex Ar [27]

The acceleration should be a gain of 2 km/h per second

5 0
3 years ago
(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle. How many revolutions does the object
Travka [436]

Answer: 10.34

Explanation:

Given

\omega -t graph for a particle is given

angle turned by the particle in radians is given by the area under \omega -t graph

The area is given by

A=20\times (2-0)+10(4-2)+\dfrac{1}{2}\times (20-10)\times (3-2)\\A=40+20+5=65\ rad

Revolutions(N) made by the object is given by

N=\dfrac{65}{2\pi }=10.34

4 0
3 years ago
6. Willingness to take turns is one way we can express our attitudes in
NNADVOKAT [17]
The answer is A ..........
5 0
3 years ago
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