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Brrunno [24]
3 years ago
10

How does the electric force between two charged particles change if one

Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

brainly.com/question/11848211

^ Similar/same question as yours!

The pressure between two costs is proportional to the product of the charges.

If solely one of the expenses is decreased by way of a element of 3, then the pressure is decreased with the aid of a thing of 3.

If each prices are reduced by a thing of 3, then the pressure is reduced via a issue of 9.

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Four compasses are placed around a wire, as shown. What is the best conclusion that can be drawn?
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A string that is restricted at both ends has a length of 1.50 m. what is the wavelength of the string’s fundamental frequency?
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Since it is restricted at both ends, λ/2 = length of string

λ/2 = 1.5m
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B)

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What are the principals of electric arc welding
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3 years ago
Suppose an object is launched from a point 320 feet above the earth with an initial velocity of 128 ft/sec upward, and the only
Ne4ueva [31]

Answer:

(a)Therefore the highest altitude attained by the object is =576 ft .

(b)Therefore the object takes 6 sec to fall to the ground.

Explanation:

Initial velocity: Initial velocity is a velocity from which an object starts to move.

u is usually used for notation of initial notation.

Final velocity: Final velocity is a velocity of an object after certain second from starting.

The final velocity is denoted by v.

Acceleration: The difference of final velocity and initial velocity per unit time

The S.I unit of acceleration is m/s².

(a)

Given that u= 128 ft\sec and g = 32 ft/sec².

At highest point the velocity of the object is 0 i.e v=0

Since the displacement is opposite to the gravity.

Therefore acceleration( a)= -g = -32 ft/sec².

To find the time this to happen we use the following formula

v=u+at

Here v=0

⇒0=128+(-32) t

⇒32t=128

⇒t = 4 sec

To determine the height we use the following formula

s=ut+\frac{1}{2} at^2

\Rightarrow s= (128\times4)+\frac{1}{2}\times (-32) \times4^2

⇒s= 256 ft

Therefore the highest altitude attained by the object is =(320+256)ft=576 ft .

(b)

At the highest point the velocity of the object is 0.

so u=0. a=g= 32 ft/sec²  [ since the direction of gravity and the displacement are same] s= 576 ft

To determine the time to fall we use the following formula

s=ut+\frac{1}{2} at^2

\Rightarrow 576 = (0\times t)+\frac{1}{2} \times 32 \times t^2

\Rightarrow 16\times t^2=576

\Rightarrow t^2=\frac{576}{16}

\Rightarrow t^2=36

⇒t=6 sec

Therefore the object takes 6 sec to fall to the ground.

8 0
2 years ago
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