Answer:
mass of the composite lump is 10 kg
Explanation:
given data
mass = 4 kg
to find out
mass of composite lump
solution
we know energy is conserved so
so m1 = m2 = m0 that is 4kg
and
E(1) release+ E(2) release = E(1,2) rest
so γ(1)m(1)c² + γ(2)m(2)c² = Mc² ..........................1
that why here
|v(1)| = |v(2)| = 3/5 c ......................2
and
γ = 1 / √(1 − v²/c²) .......................3
put here v = 3 and c is 5
γ = 1 /√(1 − 9/25)
γ = 5/4
so
γ(1) = γ(2) = γ = 5/4
so from equation 1
γ(1)m(1)c² + γ(2)m(2)c² = Mc²
M = 2γm0
M = 2(5/4 )(4)
M = 10 kg
so mass of the composite lump is 10 kg
This question is incomplete, the complete question is;
The Figure shows a container that is sealed at the top by a moveable piston, Inside the container is an ideal gas at 1.00 atm. 20.0°C and 1.00 L.
"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant?"
Answer:
the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
Explanation:
Given that;
P₁ = 1.00 atm
P₂ = ?
V₁ = 1 L
V₂ = 1.60 L
the temperature of the gas is kept constant
we know that;
P₁V₁ = P₂V₂
so we substitute
1 × 1 = P₂ × 1.60
P₂ = 1 / 1.60
P₂ = 0.625 atm
Therefore the pressure inside the container become 0.625 atm if the piston is moved to the 1.60 L mark while the temperature of the gas is kept constant
