Engineering requires a lot of school
<h3><u>CSMA/CD Protocol:
</u></h3>
Carrier sensing can transmit the data at anytime only the condition is before sending the data sense carrier if the carrier is free then send the data.
But the problem is the standing at one end of channel, we can’t send the entire carrier. Because of this 2 stations can transmit the data (use the channel) at the same time resulting in collisions.
There are no acknowledgement to detect collisions, It's stations responsibility to detect whether its data is falling into collisions or not.
<u>Example:
</u>
, at time t = 10.00 AM, A starts, 10:59:59 AM B starts at time 11:00 AM collision starts.
12:00 AM A will see collisions
Pocket Size to detect the collision.
![\begin{aligned}&T_{t} \geq 2 T_{P}\\&\frac{L}{B} \geq 2 T_{P}\\&L \geq 2 \times T_{P} \times B\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26T_%7Bt%7D%20%5Cgeq%202%20T_%7BP%7D%5C%5C%26%5Cfrac%7BL%7D%7BB%7D%20%5Cgeq%202%20T_%7BP%7D%5C%5C%26L%20%5Cgeq%202%20%5Ctimes%20T_%7BP%7D%20%5Ctimes%20B%5Cend%7Baligned%7D)
CSMA/CD is widely used in Ethernet.
<u>Efficiency of CSMA/CD:</u>
- In the previous example we have seen that in worst case
time require to detect a collision.
- There could be many collisions may happen before a successful completion of transmission of a packet.
We are given number of collisions (contentions slots)=4.
Distance = 1km = 1000m
![\begin{aligned}&\text { Speed }=2 \times 10^{8} \mathrm{m} / \mathrm{sec}\\ &T_{P}=\frac{1000}{2 \times 10^{8}}=(0.5) \times 10^{-5}=5 \times 10^{-6}\\ &T_{t}=5 \mu \mathrm{sec}\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%26%5Ctext%20%7B%20Speed%20%7D%3D2%20%5Ctimes%2010%5E%7B8%7D%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bsec%7D%5C%5C%20%26T_%7BP%7D%3D%5Cfrac%7B1000%7D%7B2%20%5Ctimes%2010%5E%7B8%7D%7D%3D%280.5%29%20%5Ctimes%2010%5E%7B-5%7D%3D5%20%5Ctimes%2010%5E%7B-6%7D%5C%5C%20%26T_%7Bt%7D%3D5%20%5Cmu%20%5Cmathrm%7Bsec%7D%5Cend%7Baligned%7D)
Answer:
The Bailey family has flourished during its business’ 110-year history. But Bailey Nurseries’ leaders still operate with the belief that the family doesn’t always know best. The company has grown from a one-man operation selling fruit trees and ornamental shrubs to one of the largest wholesale nurseries in the United States, thanks to insights from those who are family and those who aren’t.
“For a business to thrive, you have to ask for outside help,” says Terri McEnaney, president of the Newport-based company and a fourth-generation family member. “We get an outside perspective through family business programs, advisors and our board, because you can get a bit ingrained in your own way of thinking.”
When Bailey Nurseries chose its current leader in 2000, it brought in a facilitator who gathered insights from key employees, board members and owners. Third-generation leaders (and brothers) Gordie and Rod Bailey picked Rod’s daughter McEnaney, who had experience both inside and outside the company.
Explanation:
Answer:
![\vec F_{A} = -67500\,N\cdot (i + j)](https://tex.z-dn.net/?f=%5Cvec%20F_%7BA%7D%20%3D%20-67500%5C%2CN%5Ccdot%20%28i%20%2B%20j%29)
Explanation:
The position of each point are the following:
![A = (0\,m,0\,m,0\,m), B = (0.02\,m,0\,m,0\,m), C = (0\,m,0.02\,m,0\,m)](https://tex.z-dn.net/?f=A%20%3D%20%280%5C%2Cm%2C0%5C%2Cm%2C0%5C%2Cm%29%2C%20B%20%3D%20%280.02%5C%2Cm%2C0%5C%2Cm%2C0%5C%2Cm%29%2C%20C%20%3D%20%280%5C%2Cm%2C0.02%5C%2Cm%2C0%5C%2Cm%29)
Since the three objects report charges with same sign, then, net force has a repulsive nature. The net force experimented by point charge A is:
![\vec F_{A} = \vec F_{AB} + \vec F_{AC}](https://tex.z-dn.net/?f=%5Cvec%20F_%7BA%7D%20%3D%20%5Cvec%20F_%7BAB%7D%20%2B%20%5Cvec%20F_%7BAC%7D)
![\vec F_{A} = -\frac{k\cdot q^{2}}{r_{AB}^{2}}\cdot i - \frac{k\cdot q^{2}}{r_{AC}^{2}}\cdot j](https://tex.z-dn.net/?f=%5Cvec%20F_%7BA%7D%20%3D%20-%5Cfrac%7Bk%5Ccdot%20q%5E%7B2%7D%7D%7Br_%7BAB%7D%5E%7B2%7D%7D%5Ccdot%20i%20-%20%5Cfrac%7Bk%5Ccdot%20q%5E%7B2%7D%7D%7Br_%7BAC%7D%5E%7B2%7D%7D%5Ccdot%20j)
![\vec F_{A} = - \frac{k\cdot q^{2}}{r^{2}} \cdot (i + j)](https://tex.z-dn.net/?f=%5Cvec%20F_%7BA%7D%20%3D%20-%20%5Cfrac%7Bk%5Ccdot%20q%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D%20%5Ccdot%20%28i%20%2B%20j%29)
![\vec F_{A} = -\frac{(9 \times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}} )\cdot (3\times 10^{-9}\,C)}{(0.02\,m)^{2}}\cdot (i + j)](https://tex.z-dn.net/?f=%5Cvec%20F_%7BA%7D%20%3D%20-%5Cfrac%7B%289%20%5Ctimes%2010%5E%7B9%7D%5C%2C%5Cfrac%7BN%5Ccdot%20m%5E%7B2%7D%7D%7BC%5E%7B2%7D%7D%20%29%5Ccdot%20%283%5Ctimes%2010%5E%7B-9%7D%5C%2CC%29%7D%7B%280.02%5C%2Cm%29%5E%7B2%7D%7D%5Ccdot%20%28i%20%2B%20j%29)
![\vec F_{A} = -67500\,N\cdot (i + j)](https://tex.z-dn.net/?f=%5Cvec%20F_%7BA%7D%20%3D%20-67500%5C%2CN%5Ccdot%20%28i%20%2B%20j%29)