Answer:
The minimum value of wall thickness t=3.63 mm.
Explanation:
Given:
D=200 mm
P=4 MPa
t= Wall thickness
maximum shear stress=27.5 MPa
We know that
hoop stress 
Longitudinal stress
So maximum shear tress in plane

Now by putting the value

So t=3.36 mm
The minimum value of wall thickness t=3.63 mm.
Answer:
90
Explanation:
mean is basically taking the sum of all numbers and then dividing the sum with the number of all given numbers..
here, the mean is 9, total numbers are 10.. so the sum will be 9 multiplied by 10, that is 90.
Answer:
C = 292 Mbps
Explanation:
Given:
- Signal Transmitted Power P = 250mW
- The noise in channel N = 10 uW
- The signal bandwidth W = 20 MHz
Find:
what is the maximum capacity of the channel?
Solution:
-The capacity of the channel is given by Shannon's Formula:
C = W*log_2 ( 1 + P/N)
- Plug the values in:
C = (20*10^6)*log_2 ( 1 + 250*10^-3/10)
C = (20*10^6)*log_2 (25001)
C = (20*10^6)*14.6096
C = 292 Mbps
Answer:
The solution code is written in Java.
System.out.println(numItems);
Explanation:
Java <em>println() </em>method can be used to display any string on the console terminal. We can use <em>println()</em> method to output the value held by variable <em>numItems.</em> The <em>numItems </em>is passed as the input parameter to <em>println()</em> and this will output the value of <em>numItems</em> to console terminal and at the same time the output with be ended with a newline automatically.