Answer:
c. V2 equals V1
Explanation:
We can answer this question by using the continuity equation, which states that:
 (1)
where
A1 is the cross-sectional area in the first section of the pipe
A2 is the cross-sectional area in the second section of the pipe
v1 is the velocity of the fluid in the first section of the pipe
v2 is the velocity of the fluid in the second section of the pipe
In this problem, we are told that the pipe has a uniform cross sectional area, so:
A1 = A2
As a consequence, according to eq.(1), this means that
v1 = v2
so, the velocity of the fluid in the pipe does not change.
 
        
             
        
        
        
Answer:
  
Explanation:
given data 
types of drinking straws
- square cross-sectional shape
 - round shape 
 
solution
we know that both perimeter of the cross section are equal
so we can say that 
perimeter of square  = perimeter of circle   
4 × S = π × D 
here S is length and D is diameter 
S = 
        ....................1
and 
ratio of  flow rate through the square and circle is here 
  
  
   
   
  
 
        
             
        
        
        
Answer:
Output signal shape: square, from 0.1 to 230 MHz. Output power: -10 dBm (at a load of 50 Ohms).
Explanation:
 
        
                    
             
        
        
        
Answer:
A wheelbarrow, a bottle opener, and an oar are examples of second class levers