The three (3) demonstration drive tips for a VC-turbo engine are:
- Use your gears when overtaking and driving up a long hill.
- Warm up your engine before accelerating.
- Ensure your oil level is at the optimum gauge or level.
<h3>What is a VC-turbo engine?</h3>
A VC-turbo engine can be defined as a technologically-advanced internal combustion engine that is design and developed to be faster, especially by combining the torque and efficiency of an advanced diesel powertrain with the power of a high-performance gas engine.
<h3>The demonstration drive tips.</h3>
Basically, the three (3) demonstration drive tips for a VC-turbo engine include the following:
- Use your gears when overtaking and driving up a long hill.
- Warm up your engine before accelerating.
- Ensure your oil level is at the optimum gauge or level.
Read more on drive tips here: brainly.com/question/23968178
Answer:
hello some parts of your question is missing attached below is the missing part ( the required fig and table )
answer : The solar collector surface area = 7133 m^2
Explanation:
Given data :
Rate of energy input to the collectors from solar radiation = 0.3 kW/m^2
percentage of solar power absorbed by refrigerant = 60%
Determine the solar collector surface area
The solar collector surface area = 7133 m^2
attached below is a detailed solution of the problem
Answer / Explanation:
On the basis of the test result, Ultimate strength which is mostly known as the ultimate tensile strength is the strength attached to the ability or capacity of a structural element or material used in the test to withstand elongation forces or pull force applied to it.
WHILE,
True stress at fracture can be classified as stress or load associated to the point where yielding or fracture occurred divided by the cross-sectional area at the yield point.
Answer:
The correct answers are:
a. % w = 33.3%
b. mass of water = 45g
Explanation:
First, let us define the parameters in the question:
void ratio e =
= 
Specific gravity
=

% Saturation S =
×
=
× 
water content w =
=
a) To calculate the lower and upper limits of water content:
when S = 100%, it means that the soil is fully saturated and this will give the upper limit of water content.
when S < 100%, the soil is partially saturated, and this will give the lower limit of water content.
Note; S = 0% means that the soil is perfectly dry. Hence, when s = 1 will give the lowest limit of water content.
To get the relationship between water content and saturation, we will manipulate the equations above;
w = 
Recall; mass = Density × volume
w = 
From eqn. (2)
= 
∴ 
putting eqn. (6) into (5)
w = 
Again, from eqn (1)

substituting into eqn. (7)

∴ 
With eqn. (7), we can calculate
upper limit of water content
when S = 100% = 1
Given, 
∴
∴ %w = 33.3%
Lower limit of water content
when S = 1% = 0.01

∴ % w = 0.33%
b) Calculating mass of water in 100 cm³ sample of soil (
)
Given,
, S = 50% = 0.5
%S =
×
=
× 
0.50 = 
mass of water = 
203.2 centimeters.
This is because 1 inch = 2.54 centimeters which means multiply 80 inches X 2.54 = 203.2 centimeters.