Answer:
The displacement of the boat is 7.41 m
Explanation:
Given;
initial velocity of the motorboat, u = 6.5 m/s west
final velocity of the motorboat, v = 1.5 m/s west
acceleration of the motorboat, a = -2.7 m/s² east
The displacement of the boat is given by;
v² = u² + 2ad
where;
d is the displacement of the motorboat
1.5² = 6.5² + 2(-2.7)d
1.5² - 6.5² = -5.4d
-40 = -5.4d
d = (40) / 5.4
d = 7.41 m
Therefore, the displacement of the boat is 7.41 m
Homogenous mixtures don't have visible constituents. An example of this would be water.
Heterogenous ones have visible constituents and an example would be if you put some dirt in water and then it wouldn't mix properly and you could see the dirt in it.
Work is (force applied) x (distance through which the force moves).
Since the suitcase doesn't move up or down during the 15 minutes,
no work is done ... zero, zip, nada ... according to the real Physics
definition of 'work'.
Answer:
The answer to your question is given below
Explanation:
Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.
From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.
Remember, both objects must get to the ground at the same time..!
Let the time taken for both objects to get to the ground be t.
Time A = Time B = t
But B falls through time 2t
Therefore,
Time A = Time B = 2t
Height = 1/2gt^2
For A:
Time = 2t
dA = 1/2 x g x (2t)^2
dA = 1/2g x 4t^2
For B
Time = t
dB = 1/2 x g x t^2
Equating dA and dB
dA = dB
1/2g x 4t^2 = 1/2 x g x t^2
Cancel out 1/2, g and t^2
4 = 1
4dA = dB
Divide both side by 4
dA = 1/4 dB
