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3 years ago

A wave propagates at a well defined velocity that depends on the properties of the medium that carries the wave. True or false?

Physics

1 answer:

likoan [24]3 years ago

7 0

Answer:

True

Explanation:

A wave is generated as a result of oscillations which creates disturbances in the medium and these disturbances termed as waves propagates or travels from one point to another.

Waves can be classifies as:

Mechanical waves which requires material medium for their propagation

Electromagnetic waves which do not require any material medium to propagate.

A wave travels at a specific velocity depending on the type of the medium in which it propagates.

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The magnetic field at the earth's surface can vary in response to solar activity. During one intense solar storm, the vertical c

Natalka [10]

Answer:

$EMF = 1684.67 Volts$

Explanation:

As we know that EMF is induced in a closed conducting loop if the flux linked with the loop is changing with time

So we can say

$EMF = \frac{d\phi}{dt}$

now we have

$\phi = BA$

here since magnetic field is constant so we have

$EMF = A\frac{dB}{dt}$

now we have

$A = (190 \times 10^3)(190 \times 10^3)$

$A = 3.61 \times 10^{10} m^2$

now we have

$EMF = 3.61\times 10^{10} (\frac{2.8 \times 10^{-6}T}{60 s})$

$EMF = 1684.67 Volts$

6 0

2 years ago

Why can’t a real machine ever have 100% efficiency

Harman [31]

Answer:

Almost all machines require energy to offset the effects of gravity, friction, and air/wind resistance. Thus, no machine can continually operate at 100 percent efficiency.

4 0

2 years ago

A bubble of air is rising up through the ocean. When it is at a depth of 20.0 m below the surface, where the temperature is 5.00

kotegsom [21]

Answer:

the volume is 0.253 cm³

Explanation:

The pressure underwater is related with the pressure in the surface through Pascal's law:

P(h)= Po + ρgh

where Po= pressure at a depth h under the surface (we assume = 1atm=101325 Pa) , ρ= density of water ,g= gravity , h= depth at h meters)

replacing values

P(h)= Po + ρgh = 101325 Pa + 1025 Kg/m³ * 9.8 m/s² * 20 m = 302225 Pa

Also assuming that the bubble behaves as an ideal gas

PV=nRT

where

P= absolute pressure, V= gas volume ,n= number of moles of gas, R= ideal gas constant , T= absolute temperature

therefore assuming that the mass of the bubble is the same ( it does not absorb other bubbles, divides into smaller ones or allow significant diffusion over its surface) we have

at the surface) PoVo=nRTo

at the depth h) PV=nRT

dividing both equations

(P/Po)(V/Vo)=(T/To)

V=Vo*(Po/P)(T/To) = 0.80 cm³ * (101325 Pa/302225 Pa)*(277K/293K) = 0.253 cm³

V = 0.253 cm³

3 0

2 years ago

A Nichrome wire 44 cm long and 0.30 mm in diameter is connected to a 3.1 V flashlight battery. What is the electric field inside

Alexeev081 [22]

Answer:

7.05 Volts/m

Explanation:

L = length of the Nichrome wire = 44 cm = 0.44 m

V = Potential difference across the end of the wire = battery voltage = 3.1 Volts

E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

$E = \frac{V}{L}$

Inserting the values

$E = \frac{3.1}{0.44}$

E = 7.05 Volts/m

4 0

2 years ago

You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change

Sophie [7]

The change in potential energy of an object is given by
$U=mg \Delta h$
where
m is the mass of the object
g is the gravitational acceleration
$\delta h$ is the increase in altitude of the object

In our problem, $m=2.5 kg$ is the mass of the book, $g=9.81 m/s^2$ and
$\Delta h=2.6 m -1.2 m=1.4 m$ is the increase in altitude of the book, so its variation of potential energy is
$U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J$

8 0

3 years ago