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Alenkinab [10]
3 years ago
11

a force of 1.35 newtons is required to accelerate a book by 1.5 meters/second2 along a frictionless surface. what is the mass of

the bo
Physics
1 answer:
Masja [62]3 years ago
6 0

Hi there!

Recall Newton's Second Law:

\large\boxed{\Sigma F = ma}}

∑F = Net force (N)

m = mass (kg)

a = acceleration (m/s²)

Rearrange the equation to solve for mass.

Working equation:

\large\boxed{m = \frac{F}{a}}

Plug in the given values:

\frac{1.35}{1.5} = \boxed{.9 kg}

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<u>Answer:</u>

<em>Equivalence point and end point are terminologies in pH titrations and they are not the same. </em>

<u>Explanation:</u>

In a <em>titration the substance</em> added slowly to a solution usually through a pippette is called titrante and the solution to which it is added is called titrand. In acid-base titrations acid is added to base or base is added to acid.the strengths of the <em>acid and base titrated</em> determines the nature of the final solution.

At equivalence point the <em>number of moles of the acid</em> will be equal to the number of moles of the base as given in the equation.  The nature of the final solution determines the <em>pH at equivalence point. </em>

<em>A pH less than 7 will be the result if the resultant is acidic and if it is basic the pH will be greater than 7. </em>In a strong base-strong acid and weak base-weak acid titration the pH at the equivalence point will be 7 indicating <em>neutral nature of the solution. </em>

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3 years ago
two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale
Viefleur [7K]
Two thermometers, calibrated in celsius and fahrenheit respectively, are put into a liquid. the reading on the fahrenheit scale is four times the reading on the celsius scale. the temperature of the liquid is:

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2. The light from the Sun reaches Earth in 8.3 minutes. The speed of light is 11,184,681 miles/minute. How far is
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Explanation:

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2 years ago
You are standing on the SCALE<br> The scale is on the floor.<br> What are the forces on the SCALE?
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Explanation:

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If a planet has the same mass as the earth, but has twice the radius, how does the surface gravity, g, compare to g on the surfa
shepuryov [24]

Answer:

The surface gravity g of the planet is 1/4 of the surface gravity on earth.

Explanation:

Surface gravity is given by the following formula:

g=G\frac{m}{r^{2}}

So the gravity of both the earth and the planet is written in terms of their own radius, so we get:

g_{E}=G\frac{m}{r_{E}^{2}}

g_{P}=G\frac{m}{r_{P}^{2}}

The problem tells us the radius of the planet is twice that of the radius on earth, so:

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If we substituted that into the gravity of the planet equation we would end up with the following formula:

g_{P}=G\frac{m}{(2r_{E})^{2}}

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When simplifying the ratio we end up with:

\frac{g_{P}}{g_{E}}=\frac{1}{4}

So the gravity acceleration on the surface of the planet is 1/4 of that on the surface of Earth.

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