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Leya [2.2K]
3 years ago
5

You can enter compound units that are combinations of other units that are multiplied together.Torque can be calculated by multi

plying the force (N ) applied at 90∘ to the lever arm at a distance (m ) from the pivot point (point of rotation), the compound SI unit for the torque is N⋅m . If the force (at 90∘ to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?Express the torque using two significant figures and include the appropriate units.
Physics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

3.0 x 10¹ Nm

Explanation:

Torque = F x r

Where F is force applied and r is perpendicular distance from pivot point . r

is also called lever arm

Here F = 15 N and r = 2.0 m

Torque

= 15 N X 2.0 m

= 3.0 10¹ Nm.

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A nonconducting sphere has radius R = 1.29 cm and uniformly distributed charge q = +3.83 fC. Take the electric potential at the
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Answer:

a) -2.516 × 10⁻⁴ V

b) -1.33 × 10⁻³ V

Explanation:

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The potential at a distance can be represented as:

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r = 0.56 cm

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Substituting our values; we have:

V(r) = -\frac{(3.83*10^{-15}C)(0.560*10^{-2}m)^2}{8 \pi (8.85*10^{-12}F/m)(1.29*10^{-2}m)^3}

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The difference between the radial distance  and center can be expressed as:

V(r) - V(0) = -\int\limits^R_0 {\frac{kqr}{R^3} } \, dr^2

V(r) - V(0) =  [\frac{qr^2}{8 \pi E_0R^3 }]^R

V(r) = -\frac{qR^2}{8 \pi E_0R^3 }

V(r) = -\frac{q}{8 \pi E_0R }

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V(r) = -0.00133

V(r) = - 1.33 × 10⁻³ V

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