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Nookie1986 [14]
3 years ago
9

Plz help me plz I'm so stuck plz and if ur not gonna help then don't put these absurd answers for fun I'm not plaYing around her

e

Mathematics
1 answer:
olganol [36]3 years ago
7 0
There is an app called photo math I’m not sure if you have heard about it but it’s free. I’m not to good at math so I use it often. You should download it. You take a picture of the problem and it gives you step by step directions on how to solve each problem.
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Miss Violet is buying granola bars for her students. She already has 16 granola bars in her desk and needs a total of 100 bars.
masha68 [24]

Answer:

100 - 16 = 84, and 84 divided by 12 is 7. She needs to buy 7 more boxes of granola bars for her students.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the y-intercept of 2g(x)+3x=6?
umka21 [38]

The y-intercept is basically the value of the output of the function, g(x), when x=0.

Let's replace g(x) with the variable y to make this look a bit simpler.

2y + 3x = 6

Now, we enter the value of x=0 to get the y-intercept.

2y + 0 = 6

2y = 6

Divide both sides by 2

y = 3

The value of y is 3. Now enter the values of x=0 and y=3 into point-form (x,y) to get (0,3). You should know which answer choice to choose now.

Have an awesome day!

8 0
3 years ago
Las medidas de una pieza de loseta son de 45.7 x 30.5. ¿Cuál es el área de la pieza?
max2010maxim [7]
1,393.85 es la area de la pieza
6 0
3 years ago
Find the 23rd term of this sequence -25,-15,-5,5....
notsponge [240]

Answer:

195

Step-by-step explanation:

To find the 23rd term of this sequence, we can use the arithmetic sequence formula a_{n} =a_{1} +(n-1)d where,

a_{n} = n^{th} term

a_{1} = first term

n = term position

d = common difference

a_{23}=-25+(23-1)10

a_{23} =195

8 0
3 years ago
The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th
ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}

By doing so, we find:

|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1

4 0
3 years ago
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