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dmitriy555 [2]
2 years ago
14

in the process of baking a cake, the recipe calls for 4 eggs 3 cups of flour 5 teaspoons of baking powder 1/3 pound of butter an

d 1.5 cups of sugar a baker has the following available 6 dozen eggs 48 cups of flour 45 teaspoons of baking powder 9 pounds of butter and 30 cups of sugar which is the limiting reactant in this process
Chemistry
1 answer:
Minchanka [31]2 years ago
4 0

Answer: Baking powder

Explanation: 45/5=9 cakeworth’s and the other reactants allow more than 9.

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A chemist titrates 150.0 mL of a 0.2653 M carbonic acid (H2CO3) solution with 0.2196 M NaOH solution at 25 °C. Calculate the pH
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Answer:

9.3

Explanation:

This is long and complicated so get ready

We are going to use the conjugate base of carbonic acid with water to make carbonic acid and OH- (Na is simply a spectator ion and is irrelavent here)

Let the conjugate base be A- and Carbonic acid be HA

A- + H20 ⇄ HA + OH-

To find the concentration of A- we must find the concentration of the reactants given. We know this will be equal because it is a strong base and all of it disassociates.

to get moles of acid we take the concentration and multiply by liters to cancel

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Because it is at equivalence point we know the moles will be equal. We are given the concentration so we only have to solve for liters

We plug it into the equation and found: .181 L

Now use moles and combined volums to fins concentrarion which is .120 M

Now plug that use the Ka converted to Kb to find the cincentrations of HA and OH-

Ka is (10^-3.60) = 2.4E-4

Kb x Ka is 10^-14

Kb = 3.98E-11

Now we know Kb = [HA] [OH] / [A-]

Solve for this through algebra by using x for the values you dont know

youll find x^2 = 3.3E-10

X = 1.8 E -5

this is the OH- concentration

-log [oh] = pOH

pOH = 4.73

We know 14-pOH = ph so pH= 9.3

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There the neutralization reaction is:

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