Oxidation states number (OSN) show how many electrons gained, lost or shared during chemical reactions.
Here are some rules of oxidation state numbers.
1. OSN of 1A elements in compounds is +1
2. OSN of Oxygen in compounds is -2
3. Sum of OSN of elements equals zero in neutral compounds.
4. OSN of free elements is zero. ex. F2, N2, O2.. all have 0 OSN.
If an element loses electrons during reaction, it is oxidized. That element is called as reducing agent.
If an element gains electrons during reaction, it is reduced. That element is called as oxidizing agent.
In the given reaction, potassium perchlorate decompose into potassium chlorate and oxygen.
a) KClO4.
K (potassium) is 1A element, OSN +1,
Oxygen in the compound has OSN -2.
Let OSN of Cl be x
1+ x+(4*-2)=0 (since compound is neutral)
Solve the equation. X is equal to +7.
b)Potassium perchlorate is the reactant, Potassium chloride and Oxygen are the products.
Reactants -----> Products
c) Check out change of OSN of elements.
in KCl, OSN number of K is +1, Cl is -1. So Cl+7---->Cl-1. It takes 8 electrons. It was reduced.
in KClO4, OSN number of O is -2, in O2 it becomes O. So O-2---->O. It gives electrons. It was oxidized.
Shortly,
LOSS OF ELECTRONS=OXIDIZED
GAIN OF ELECTRONS=REDUCED
Answer:
1,6,8
Explanation:
Periodic Table- H=1.C=6,O=8
Hydrogen is H, Carbon is C, Oxygen is O
Bend ss so think what’s hallienring is that tray okay Whitley
Alkali: Group 1(I A). Halogens: group 17 (VII A)
mass of N₂ = 25.76 g
mass of O₂ = 58.88 g
Explanation:
Nitrogen (N₂) will react with oxygen (O₂) to form trinitrogen tetroxide (N₂O₄).
N₂ + 2 O₂ → N₂O₄
number of moles = mass / molecular weight
number of moles of N₂O₄ = 85 / 92 = 0.92 moles
Knowing the chemical reaction we devise the following reasoning:
if 1 moles of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄
then X moles of N₂ react with Y moles of O₂ to produce 0.92 moles of N₂O₄
X = (1 × 0.92) / 1 = 0.92 moles of N₂
Y = (2 × 0.92) / 1 = 1.84 moles of O₂
mass = number of moles × molecular weight
mass of N₂ = 0.92 × 28 = 25.76 g
mass of O₂ = 1.84 × 32 = 58.88 g
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