Answer:
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Step-by-step explanation:
(This can be simplified, because when you divide expressions with exponents that have the same bases, you can subtract the exponents from the one with the corresponding base)
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=
(Simplify)
= 
Answer:
(A) 0.04
(B) 0.25
(C) 0.40
Step-by-step explanation:
Let R = drawing a red chips, G = drawing green chips and W = drawing white chips.
Given:
R = 8, G = 10 and W = 2.
Total number of chips = 8 + 10 + 2 = 20

As the chips are replaced after drawing the probability of selecting the second chip is independent of the probability of selecting the first chip.
(A)
Compute the probability of selecting a white chip on the first and a red on the second as follows:

Thus, the probability of selecting a white chip on the first and a red on the second is 0.04.
(B)
Compute the probability of selecting 2 green chips:

Thus, the probability of selecting 2 green chips is 0.25.
(C)
Compute the conditional probability of selecting a red chip given the first chip drawn was white as follows:

Thus, the probability of selecting a red chip given the first chip drawn was white is 0.40.
False: You can't use the commutative property on subraction.
<span>answer is A. 35%
182 / 280 = 0.65
0.65 = 65%
100% - 65% = 35%</span>
Answer:
F(x) = x + 2
g(x) = x - 4
(f g)(x) =
Step-by-step explanation: