Answer:
![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5Cfrac%7B1200%7D%7B499%7D%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A2.40480%5Cdots%20%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A%5Cfrac%7B1200%7D%7B499%7D%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
![20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\\frac{499x}{499}\le \frac{1200}{499}\\Simplify\geq \\x\le \frac{1200}{499}](https://tex.z-dn.net/?f=20%5Cge%20%5C%3A8%2B4.99x%5C%5CSwitch%5C%3Asides%5C%5C8%2B4.99x%5Cle%20%5C%3A20%5C%5C%5Cmathrm%7BMultiply%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D100%5C%5C8%5Ccdot%20%5C%3A100%2B4.99x%5Ccdot%20%5C%3A100%5Cle%20%5C%3A20%5Ccdot%20%5C%3A100%5C%5CRefine%5C%5C800%2B499x%5Cle%20%5C%3A2000%5C%5C%5Cmathrm%7BSubtract%5C%3A%7D800%5Cmathrm%7B%5C%3Afrom%5C%3Aboth%5C%3Asides%7D%5C%5C800%2B499x-800%5Cle%20%5C%3A2000-800%5C%5CSimplify%5C%5C499x%5Cle%20%5C%3A1200%5C%5C%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D499%5C%5C%5Cfrac%7B499x%7D%7B499%7D%5Cle%20%5Cfrac%7B1200%7D%7B499%7D%5C%5CSimplify%5Cgeq%20%5C%5Cx%5Cle%20%5Cfrac%7B1200%7D%7B499%7D)
(88sin20)(t - 16t²) = 0
(8(0.3090169944)(t - 16t²) = 0
(2.472135955)(t - 16t²) = 0
2.472135955t - 39.55417528t² = 0
Answer:
22=-7
Step-by-step explanation:
the anwser is 36...................
Answer: The area of the regions covered by grass is approximately 313.375 sq ft.
Step-by-step explanation:
Given: A company is building a new park in the shape of a circle with a 25 ft diameter.
Then radius = ![\dfrac{25}{2}=12.5\ ft](https://tex.z-dn.net/?f=%5Cdfrac%7B25%7D%7B2%7D%3D12.5%5C%20ft)
Required area = Area of circle - Area of rectangle + Area of triangle
Formula: Area of circle = ![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
Area of rectangle = length x width
Area of triangle = 0.5 x base x height
Area of circle = ![(3.14)(12.5)^2=490.625\ \text{ft}^2](https://tex.z-dn.net/?f=%283.14%29%2812.5%29%5E2%3D490.625%5C%20%5Ctext%7Bft%7D%5E2)
Area of rectangle = 20 ft x 10ft = 200 ft²
Area of triangle = 0.5 x 7 x 6.5 = 22.75 ft²
Required area = 490.625 -200+22.75 = 313.375 ft²
Hence, The area of the regions covered by grass is approximately 313.375 sq ft.