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gayaneshka [121]
3 years ago
14

Baby polar bears learn how to hunt for fish and seals by watching their mother do it.

Chemistry
1 answer:
adoni [48]3 years ago
6 0

Answer:

A

Explanation:

they watched there mother

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you can identify the properties of an element by studying its_____ on the ... between metals and nonmetals on the periodic table are the _____ which have ...

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Sheela wants to make a computer model of a land ecosystem. Part of her model simulates the chemical processes of photosynthesis
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H2(g) + Co(g) _CH3OH<br> balance the equation <br>​
Tom [10]

Answer:

CO + 2H2 = CH3OH

Explanation:

1. Label Each Compound With a Variable

  aCO + bH2 = cCH3OH

2. Create a System of Equations, One Per Element

  C: 1a + 0b = 1c

  O: 1a + 0b = 1c

  H: 0a + 2b = 4c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 1

  b = 2

  c = 1

4. Substitute Coefficients and Verify Result

  CO + 2H2 = CH3OH

      L R

  C: 1 1 ✔️

  O: 1 1 ✔️

  H: 4 4 ✔️

8 0
2 years ago
A 2.0-liter volume of hydrogen gas combined with 1.0 liter of oxygen gas to produce 2.0 liters of water vapor. Does oxygen uderg
lidiya [134]
Oxygen undergoes a chemical change
8 0
3 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
3 years ago
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