Answer:
- Calculate the additional CPI due to the icache stalls.
- Calculate the additional CPI due to the dcache stalls.
- Calculate the overall CPI for the machine.
The additional CPI due to icache stalls = Hit Rate * Hit Latency + Miss Rate*
Miss Penalty = 0.9*2 + 0.1*50 = 1.8 + 5 = 6.8
The additional CPI due to dcache stalls = 0.92*2 + 0.08*124 = 11.76
The overall CPI = 0.3*11.76 + 0.7*1.0 + 1.0*6.8 = 11.03 7.
Explanation:
Answer:
The change in complex systems can be explained according to the relationship of the environment where the system is implemented.
The system environment is dynamic, which consequently leads to adaptation to the system, which generates new requirements inherent to changes in business objectives and policies. Therefore, changing systems is necessary for tuning and usefulness so that the system correctly supports business requirements.
An example is the registration of the justification of the requirements, which is a process activity that supports changes in the system so that the reason for including a requirement is understood, which helps in future changes
Explanation:
Answer:
you have to go to slides and it will say add slide and you click there and you have a slide.
Explanation:
I believe the answer is Microsoft Office, Correct me if I'm wrong.
Really hope this helps!
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
