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barxatty [35]
4 years ago
5

Precipitation clouds are observed at a distance of about 720 miles to the west of a city. The clouds are seen moving westwards a

t an average rate of 30 miles per hour. Which of these statements best predicts the weather in the city within 24 hours?
a. Rain is likely.
b. Rain is unlikely.
c. Snow is likely.
d. Snow is unlikely.
Physics
2 answers:
tankabanditka [31]4 years ago
3 0
This question may require more information for an accurate answer. If the clouds are observed west of the city and they are moving in a westerly direction it means that the clouds are moving away. Precipitation refers to rainfall, sleet, hail or snow. Since no reference was made to the temperature, season or location of the city it could be rain or snow clouds. The clouds are moving away from the city so the possible answers could be b. or d. Furthermore, by dividing the distance by the speed one would get an answer of twenty four hours. So even if the clouds were moving towards the city it would take a day to reach and precipitation would not be likely in 24 hrs.
nalin [4]4 years ago
3 0

Answer:

A) Rain is likely.

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A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber
Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}

Now calculate the bouyant force acting on the lead

F_L = Vpg

F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N

If V is the volume submerged in the water then bouyant force on the bobber is

F_B=V'pg

Equate bouyant force with the tension and gravitational force

F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}

Now Total volume of bobble is

\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\

=\large\boxed{4.52 \%}

7 0
3 years ago
How high will a ball go if thrown at 10m/s up?
antiseptic1488 [7]
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4 0
3 years ago
What voltage produces a current of 50 amps with a resistance of 20 ohms?<br>​
PIT_PIT [208]

Answer:

1000 V

Explanation:

Ohm's law:

V = IR

V = (50 A) (20 Ω)

V = 1000 V

5 0
3 years ago
A bouncy ball is being thrown upwards with a velocity of 34 meters per second if you caught the ball at the same height you rele
Serga [27]

It took the ball 6.94 seconds to make the trip

Explanation:

A bouncy ball is being thrown upwards with a velocity of 34 meters per

second and you caught the ball at the same height you released it

1. The initial velocity of the ball is 34 m/s upward

2. The acceleration of gravity is -9.8 m/s²

3. You caught the ball at the same height you released it

We need to find how long it takes the ball to make the trip

You caught the ball at the same height you released it, then

→ The displacement of the trip s =  zero meter

→ The ball thrown upward with initial velocity u = 34 m/s

→ The acceleration of gravity g = -9.8 m/s²

→ s = u t + \frac{1}{2} g t²

Substitute the values of u , g , s in the rules

→ 0 = 34 t + \frac{1}{2} (-9.8) t²

→ 0 = 34 t - 4.9 t²

Multiply both sides by -1

→ 4.9 t² - 34 t = 0

Take t as common factor

→ t(4.9 t - 34) = 0

Equate each factor by 0

→ t = 0 ⇒ initial position

→ 4.9 t - 34 = 0

Add 34 to both sides

→ 4.9 t = 34

Divide both sides by 4.9

→ t = 6.94 seconds ⇒ final position

It took the ball 6.94 seconds to make the trip

Learn more:

You can learn more about free fall in brainly.com/question/5531630

#LearnwithBrainly

5 0
4 years ago
Three force vectors are added together. One has a magnitude of 9 N, the second one a magnitude of 18 N, and the third a magnitud
fgiga [73]

Answer:

true I, II and III

Explanation:

The force is a vector quantity, by local it must be added as vectors, we can suppose several cases

.i) the vectors are colonial, so their sum is maximum

       F_max = 9 + 15 + 18

       F_max = 42 N

This is the maximum value

ii) the anti-parallel vectors giving a minimum value

     F_min = 15 + 9-18

     F_min = 6 N

iii) the vectors have angles between them, so we must use the Pythagorean theorem to find the resultant, which is an intermediate value between the two extreme values ​​found.

Let's take a look at each statement

I) True This is the maximum value of the force if all the vectors are colonial

II) True The minimum value is 6 N, so zero can never be reached

III) True these bores are between the maximum values ​​and the direction of the vectors, lower values ​​occur when the forces have angular between them

IV) False. Force can never reach zero

V) False. Several of the above are conclusions of the exercise

7 0
3 years ago
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