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3 years ago

What would happen to the moon if the earth stopped exerting the force of gravity onto it?

1 answer:

nataly862011 [7]3 years ago

5 0

It would drift away from the Earth and enter its own orbit around the sun. It would become the 9th planet, in an orbit very close to Earth's orbit. (Our moon is larger than Pluto, and almost as large as Mercury.)

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What causes sounds that are lower than 0 decibels?

vichka [17]

Answer:

So 0 dB does not mean no sound, it means a sound level where the sound pressure is equal to that of the reference level. This is a small pressure, but not zero. It is also possible to have negative sound levels: - 20 dB would mean a sound with pressure 10 times smaller than the reference pressure, i.e. 2 μPa.

4 0

2 years ago

Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is abo

hoa [83]

To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.

Our values are given as

$f = 4.11 *10^{12} Hz$

$A = 1.23 * 10^{-11}m$

The angular velocity of a body can be described as a function of frequency as

$\omega = 2\pi f$

$\omega = 2\pi 4.11 *10^{12}$

$\omega=2.582*10^{13} rad/s$

PART A) The expression for the maximum angular velocity is given by the amplitude so that

$V = A\omega$

$V =( 1.23 * 10^{-11})(2.582*10^{13})$

$V = = 317.586m/s$

PART B) The maximum acceleration on your part would be given by the expression

$a = A \omega^2$

$a =( 1.23 * 10^{-11})(2.582*10^{13})^2$

$a= 8.2*10^{15}m/s^2$

4 0

3 years ago

uppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s

Paul [167]

Answer:

t = 22.2 s

Explanation:

angular distance covered in the 36.0 s is

θ = ω(avg)t = ½(10.0 + 30.0)36 = 720 radians

720/2 = 360 radians

α = Δω/t = (30 - 10)/36 = 5/9 rad/s²

θ = ω₀t + ½αt²

360 = 10.0t + ½(5/9)t²

0 = (5/18)t² + 10.0t - 360

0 = t² + 36t - 1296

t = (-36 ±√(36² - 4(1)(-1296))) / 2

t = (-36 ±√(6480)) / 2

t = -18 ±√1620

we ignore the negative time result as it occurs before we care.

t = -18 + √1620 = 22.249223... s

8 0

3 years ago

A cruise ship travels directly toward the dock at a speed of 12 m/s

Hatshy [7]

Thanks for sharing that information. After extensive calculation,
we can say with assurance that after some number of seconds,
a loud "crunch" is perceived by the souls aboard the ill-fated vessel.

3 0

3 years ago

An Olympic high jumper, with a mass of 82 kg, has a

Digiron [165]

Answer:

I don't really know

Explanation:

I really wanted to help you, but then I realized i didnt know how to

8 0

2 years ago