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Svetlanka [38]
3 years ago
11

At one instant, an electron (charge = –1.6 x 10–19 C) is moving in the xy plane, the components of its velocity being vx = 5.0 x

105 m/s and vy = 3.0 x 105 m/s. A magnetic field of 0.80 T is in the positive y direction. At that instant, what is the magnitude of the magnetic force on the electron?
Physics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

The direction of force is along negative Z axis and the magnitude of force is

6.4 x 10^-14 N.

Explanation:

q = - 1.6 x 10^-19 c

vx = 5 x 10^5 m/s, vy = 3 x 10^5 m/s, B = 0.8 T along Y axis

The velocity vector is given by

v = 5 x 10^5 i + 3 x 10^5 j

B = 0.8 j

Force on a charged particle place in a magnetic field is given by

F = q (v x B)

F = -1.6 x 10^-19 {(5 x 10^5 i + 3 x 10^5 j) x (0.8 j)}

F = - 1.6 x 10^-19 (5 x 0.8 x 10^5 k)

F = - 6.4 x 10^-14 k

The direction of force is along negative Z axis and the magnitude of force is

6.4 x 10^-14 N.

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Suppose that you are holding a pencil balanced on its point. If you release the pencil and it begins to fall, what will be the a
Naily [24]

Answer:

The angular acceleration of the pencil<em> α  = 17 rad·s⁻²</em>

Explanation:

Using Newton's second angular law or torque to find angular acceleration, we get the following expressions:

    τ = I α                              (1)

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The weight is that the pencil has is,

   sin 10 = r / (L/2)

   r = L/2(sin(10))

 

The shape of the pencil can be approximated to be a cylinder that rotates on one end and therefore its moment of inertia will be:

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   α  = 3/2(9.8) / 0.150sin(10)

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3 years ago
Air enters a turbine operating at steady state with a pressure of 75 Ibf/in.^2, a temperature of 800º R and velocity of 400 ft/s
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Answer:

(a) W/m = 49.334 Btu/lb

(b) \frac{E_{d} }{m} = 22.12 Btu/lb

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Specific enthalpy (h_{1}) = 191.81 BTu/lb

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At the temperature (T_{2})of 600 ºR and pressure (P_{2}) of 15 Ibf/in.^2, we can deduce that:

Specific enthalpy (h_{2}) = 143.47 BTu/lb

Specific entropy (s_{2}) = 0.6261 Btu/(lb.ºR)

The work done can be calculated using energy rate equation:

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