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AlexFokin [52]
3 years ago
11

What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr]

5s2 5d10 5p6 6s2 6d10 6p3 E. [Xe] 6s2 5d10 6p3
Chemistry
2 answers:
BaLLatris [955]3 years ago
6 0

Answer: C. [Xe] 4f^{14}5d^{10}6s^26p^3

Explanation: Bismuth is an element with atomic number of 83 and contains  83 electrons. The nearest noble gas is Xenon with symbol Xe and contains 54 electrons.

The electronic configuration of Bismuth in terms of nearest noble gas Bi is :

[Xe] 4f^{14}5d^{10}6s^26p^3

OlgaM077 [116]3 years ago
4 0

The answer is C) Xe 4f14 5d10 6s2 6p3

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D. Liquid Nitrogen is much colder than Water.
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when propene gas (C3H6) is added to bromine liquid, another liquid is produced which has the formula C3H6Br2. what is the chemic
klio [65]

Answer:

C3H6 + Br2 → C3H6Br2

Explanation:

The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:

  • C3H6 + Br2 → C3H6Br2

We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.

4 0
2 years ago
How do you calculate the number of moles in CO2
gogolik [260]

Answer:

The number of molecules in a mole (known as Avogadro's constant) is defined such that the mass of one mole of a substance, expressed in grams, is equal to the mean molecular mass of the substance. The molecular mass of CO2 = 12+2x16 = 44, so the mass of a mole of CO2 is approximalty 44 grams

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3 0
3 years ago
A 0.0000792 M sample of Compound X in a solvent has an absorbance of 0.341 at 528 nm in a 1.000-cm cuvet. The solvent alone has
natima [27]

Answer:

a) a = 3485 M⁻¹cm⁻¹

b) C = 0,000127 M

Explanation:

Lambert-Beer law says that there is a linear relationship between absorbance and concentration of a chemical substance. The formula is:

A = a×b×C

Where A is absorbance, a is molar absorptivity, b is path length and C is concentration.

a) In the problem Concentration is 0.0000792 M, b is 1,000cm and Absorbance is absorbance of sample-absorbance of blank: 0,341-0,065 = 0,276

Replacing:

0,276 = a×1,000cm×0,0000792M

<em>a = 3485 M⁻¹cm⁻¹</em>

b) As the experiment consist in the same compound in the same solvent, the molar absorptivity will be the same, a = 3485 M⁻¹cm⁻¹, path length will be 1,000cm and absorbance: 0,508-0,065 = 0,443

Replacing:

0,443 = 3485 M⁻¹cm⁻¹×1,000cm×C

<em>C = 0,000127 M </em>

<em></em>

I hope it helps!

8 0
3 years ago
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