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AlexFokin [52]
3 years ago
11

What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr]

5s2 5d10 5p6 6s2 6d10 6p3 E. [Xe] 6s2 5d10 6p3
Chemistry
2 answers:
BaLLatris [955]3 years ago
6 0

Answer: C. [Xe] 4f^{14}5d^{10}6s^26p^3

Explanation: Bismuth is an element with atomic number of 83 and contains  83 electrons. The nearest noble gas is Xenon with symbol Xe and contains 54 electrons.

The electronic configuration of Bismuth in terms of nearest noble gas Bi is :

[Xe] 4f^{14}5d^{10}6s^26p^3

OlgaM077 [116]3 years ago
4 0

The answer is C) Xe 4f14 5d10 6s2 6p3

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Draw an alkyl bromide with proper stereochemistry that can be used to synthesize the given alkene as the exclusive product via a
enot [183]

Answer:

See explanation below

Explanation:

You forgot to put the picture to do so. In this case, I manage to find one, and I hope is the one you are looking for. If not, then post it again and I'll gladly help you out again.

According to the picture with the answer, we have a cyclohexane with 4 methyl groups there. Two of them are facing towards the molecule with a darker bond. This means that the alkyl bromide, should have a bromine in one of the bonds, and in order to produce an E2 reaction, this bromine should be facing in the opposite direction of the methyl groups which are facing towards. This is because an E2 reaction occurs with the less steric hindrance in the molecule. If the bromine is in the same direction as the methyl group, it will cause a lot more of work to do a reaction, and therefore, an E2 reaction. I will promote instead a E1 or a sustitution product.

Therefore the alkyl bromide should be like the one in the picture 2.

3 0
3 years ago
Why is granite better then marble for a statue in a city centre
nasty-shy [4]
Granite is stronger, and it doesn't grow mold in the rain. It also looks better than marble and is easier to carve. 
5 0
3 years ago
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ASAP worth 15 points also
Taya2010 [7]
The person above me is correct I took a test on this so it’s the right answer
7 0
3 years ago
4. A 0.51 kg solution contains 87 mg of potassium iodide. Calculate the W/W concentration
anzhelika [568]

Taking into account the definition of percentage composition, the percent composition of potassium iodide in this sample is 0.017%.

<h3>Definition of percent composition </h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

To calculate the percentage of composition, it is necessary to know the mass of the element in a known mass of the compound.

<h3>Percentage Composition in this case</h3>

In this case, you know that a 0.51 kg (or 510000 mg, being 1 kg= 1000000 mg) solution contains 87 mg of potassium iodide.

Dividing the mass amount of potassium iodide present in the compound by the mass of the sample and multiplying it by 100 to obtain a percentage value, the percentage composition of potassium iodide is obtained:

percentage composition of potassium iodide=\frac{87 mg}{510000 mg} x100

<u><em>percentage composition of potassium iodide= 0.017%</em></u>

Finally, the percent composition of potassium iodide in this sample is 0.017%.

Learn more about percent composition:

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brainly.com/question/9779410

brainly.com/question/17030163

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2 years ago
To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu
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I believe it would be better to use an orbital designation than the written configuration, if the number of electrons in the ground state of the atom are quite high for the given element, as above 50, for instance.

This saves space and also one can see the discrete quantized energy levels associated with the subshells of the main energy levels if written in orbital designation.
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