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dlinn [17]
3 years ago
14

A e B são dos blocos de massas 3,0 kg e 2,0 kg, respectivamente, que se movimentam juntos sobre uma superficie horizontal e perf

eitamente lisa. F é uma força de intensidade 30 N aplicada ao bloco A. A aceleração do sistema e a intensidade da força que B exerce em A são , respectivamente :
Physics
1 answer:
makvit [3.9K]3 years ago
6 0

F = m*a

30 N = (ma + mb) * a

30 = 5*a

a = 6 m/s ^2

F de B em A

30 - F de B,A = ma * a

30 - F de B em A = 3 * 6

30 - 18 = F de B em A

12 = F de B em A


Resposta: 6 m/s^2 e 12N

Bate com o gabarito, man? Ou eu tô viajando aqui?

Abç!

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Which statement describes ionic compounds?
sladkih [1.3K]

Answer:the answer is b

Explanation:

This is because in an ionic bond negative and positive bonds are present

8 0
2 years ago
The intensity of light from a central source varies inversely as the square of the distance. If you lived on a planet only half
sertanlavr [38]

Answer:

the intensity will be 4 times that of the earth.

Explanation:

let us assume the following:

intensity of light on earth =J

distance of earth from sun = d

intensity of light on other planet = K

distance of other planet from sun = \frac{d}{2} (from the question, the planet is half as far from the sun as earth)

from the question the intensity is inversely proportional to the square of the distance, hence

  • intensity on earth : J = \frac{1}{d^{2} }

        Jd^{2} = 1 ... equation 1

  • intensity on other planet : K =  \frac{1}{(\frac{d}{2}) ^{2} }  (the planet is half as far from the sun as earth)

        K(\frac{d}{2}) ^{2} = 1 ....equation 2

  • equating both equation 1 and 2 we have

       Jd^{2} = K(\frac{d}{2}) ^{2}

       Jd^{2} = K\frac{d^{2}}{4}

       J = \frac{K}{4}

        K = 4J

       intensity of light on other planet (K) = 4 times intensity of light on earth (J)

5 0
2 years ago
You are a member of a geological team in Central Africa. Your team comes upon a wide river that is flowing east. You must determ
Dovator [93]

Answer:

(a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

Explanation:

Given that,

Constant speed = 6.00 m/s

Time = 20.1 sec

Speed = 9.00 m/s

Time = 11.2 sec

We need to write a equation for to travel due north across the river,

Using equation for north

v^2-c^2=\dfrac{w^2}{t^2}

Put the value in the equation

6.00^2-c^2=\dfrac{w^2}{(20.1)^2}

36-c^2=\dfrac{w^2}{404.01}....(I)

We need to write a equation for to travel due south across the river,

Using equation for south

v^2-c^2=\dfrac{w^2}{t^2}

Put the value in the equation

9.00^2-c^2=\dfrac{w^2}{(11.2)^2}

81-c^2=\dfrac{w^2}{125.44}....(II)

(a). We need to calculate the wide of the river

Using equation (I) and (II)

45=\dfrac{w^2}{125.44}-\dfrac{w^2}{404.01}

45=w^2(0.00549)

w^2=\dfrac{45}{0.00549}

w=\sqrt{\dfrac{45}{0.00549}}

w=90.5

We need to calculate the current speed

Using equation (I)

36-c^2=\dfrac{(90.5)^2}{(20.1)^2}

36-c^2=20.27

c^2=20.27-36

c=\sqrt{15.73}

c=3.96\ m/s

(b). We need to calculate the shortest time

Using formula of time

t=\dfrac{d}{v}

t=\dfrac{90.5}{6}

t=15.0\ sec

We need to calculate the distance

Using formula of distance

d=vt

d=3.96\times15.0

d=59.4\ m

Hence, (a). The width of the river is 90.5 m.

The current speed of the river is 3.96 m.

(b). The shortest time is 15.0 sec and we would end 59.4 m east of our starting point.

3 0
3 years ago
Question No 1 Find the voltage drop across 24 ohm resistor and current flowing through 22 ohm resistor in the given circuit as s
lord [1]

Answer:

8.25 V

Explanation:

We can ignore the 22Ω and 122Ω resistors at the bottom.  Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.

The 2Ω resistor and the 44Ω resistor are in parallel.  The equivalent resistance is:

1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω

This resistance is in series with the 12Ω resistor.  The equivalent resistance is:

1.913Ω + 12Ω = 13.913Ω

This resistance is in parallel with the 24Ω resistor.  The equivalent resistance is:

1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω

Finally, this resistance is in series with the 4Ω resistor.  The equivalent resistance of the circuit is:

8.807Ω + 4Ω = 12.807Ω

The current through the battery is:

12 V / 12.807Ω = 0.937 A

The voltage drop across the 4Ω resistor is:

(0.937 A) (4Ω) = 3.75 V

So the voltage between the bottom nodes and the top nodes is:

12 V − 3.75 V = 8.25 V

4 0
3 years ago
Anybody knows this thanks !
ss7ja [257]

Answer:

225J

Explanation:

1/2mvsq=1/2×50×9

7 0
3 years ago
Read 2 more answers
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