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dlinn [17]
3 years ago
14

A e B são dos blocos de massas 3,0 kg e 2,0 kg, respectivamente, que se movimentam juntos sobre uma superficie horizontal e perf

eitamente lisa. F é uma força de intensidade 30 N aplicada ao bloco A. A aceleração do sistema e a intensidade da força que B exerce em A são , respectivamente :
Physics
1 answer:
makvit [3.9K]3 years ago
6 0

F = m*a

30 N = (ma + mb) * a

30 = 5*a

a = 6 m/s ^2

F de B em A

30 - F de B,A = ma * a

30 - F de B em A = 3 * 6

30 - 18 = F de B em A

12 = F de B em A


Resposta: 6 m/s^2 e 12N

Bate com o gabarito, man? Ou eu tô viajando aqui?

Abç!

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Answer:

7.74m/s

Explanation:

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½KA² = ½mv² + ½kx²

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Collect like terms

KA² - Kx² = mv²

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V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

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V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

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8 0
3 years ago
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Convert 9.83 m/s with a radius of 0.85 m to rotations per minute (rpm)
marissa [1.9K]

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Explanation:

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Now, rotations take place in circular motion. So, the circumference of a circle is 2 \pi r.

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Circumference = 2 \times pi \times r\\= 2 \times 3.14 \times 0.85 m\\= 5.338 m

Formula used to calculate rotations per minute (rpm) are as follows.

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3 years ago
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F= 34.3 N

L= Fy * d

L= 49.83 J

6 0
4 years ago
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